1.if ax-y-2=0 and bx-5y+11=0 intersect at the point (3,4),fi

wxfy19692022-10-04 11:39:544条回答

1.if ax-y-2=0 and bx-5y+11=0 intersect at the point (3,4),find the values of a and b.
2.find the equation of the straight line through (3,-4) that is perpendicular to the line with x-intercept and y- intercept -2 and 5 respectively.
3.find the acute angle between the straight lines with equations 3x-y=5 and 2x-4y+1=0
4.find the exact equation of the straight line through the midpoint of (0,-5),and (4,-1) hat is perpendicular to the line that makes angle of 30degree with the x-axis

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48号楼的小白共回答了21个问题 | 采纳率95.2%: 1.ax-y-2=0和bx-5y+11=0相交在点(3,4),求a和b.
因为过点（3,4）；把点（3,4）带入,
则
3a-4-2=0
3b-20+11=0
解得a=2,b=3
2.求垂直x轴截距为2,y截距为5的直线,且过点(3,- 4)的直线方程.
x轴截距为2,y截距为5
设直线为y=kx+b
则过点（0,5）,（2,0）
代入可知该直线的斜率为：-5/2
所以所求直线的斜率为:2/5
直线又过(3,- 4)
所以方程为y+4=2/5(x-3)
即2x-5y-26=0
3.找出一次函数3x-y=5和 2x-4y+1=0 的锐角夹角
设夹角为a,则由夹角公式cosa=ab/|a||b|得
cosa=[3*2+（-1）*（-4）]/根号下[（3^2+1)(2^2+4^2)]
cosa=1/根号2
则a=45°
4.求过(0,- 5)和(4,- 1)的中点,且垂直与x轴成30°角的直线
(0,- 5)和(4,- 1)的中点为
x=（0+4）/2=2
y=（-5-1）/2=-3
与x轴成30°角的直线斜率为
k=tan30°=1/根号3
则垂直与x轴成30°角的直线斜率为
k'=-1/k=-根号3
则直线方程为y+3=根号3（x-2); 1年前

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这个函数看不懂,def intersect(seq1,seq2):res = []for x in seq1:if x 这个函数看不懂, def intersect(seq1,seq2): res = [] for x in seq1: if x in seq2: res.append(x) return res ii山东人1年前2: zhhcr126 共回答了17个问题 | 采纳率70.6%

是返回seq1∩seq2的
即输出res序列,是包含所有的元素同时属于seq1和seq2
res = [] 初始化空序列 res
for x in seq1:遍历所有seq1中的元素x
if x in seq2:判断某一个x是否存在于seq2中
res.append(x) 若是,则res中存入这个元素x
循环结束
return res 返回seq1和seq2的交集,即同属于seq1和seq2的元素

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l和m平行,两条斜线不平行,所以你可以把第二条斜线自己画的更斜一些,不要像原图中好像斜线也平行似的.这样就很容易判断了,有3个角和角a相等,无非就是对顶角同位角相等的初中知识
另外,你给的选项应该是improving sentences里面的选项,与这道题无关
In the figure above,four lines intersect as shown.If a=30度 and line L is parallel to line M ,how many of the seven angles marked with arrows must have measure 30度?
翻译
如图所示,四条相交线中角a是30度,l和M平行,7个标注出来的角度中,有多少是30度

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我们是两条永远不会交叉的交叉线.

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In the xy-coordinate plane, the graph of y =-x^2+9 intersect In the xy-coordinate plane, the graph of y =-x^2+9 intersects line l at (p,5) and (t,-7). What is the least possible value of the slope of l ? A 6 B 2 C -2 D -6 E -10 具体计算过程和答案 雪天的精灵1年前1: 我狂恋香罗梦共回答了13个问题 | 采纳率92.3%

5=-p^2+9
p^2=4
p=±2
-7=-t^2+9
t^2=16
t=±4
while (2,5) and (4,-7)
slope=(-7-5)/(4-2)=-6
while (2,5) and (-4,-7)
slope=(-7-5)/(-4-2)=2
while (-2,5) and (4,-7)
slope=(-7-5)/(4+2)=-2
while (-2,5) and (-4,-7)
slope=(-7-5)/(-4+2)=6
the answer: A B C D

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1.if ax-y-2=0 and bx-5y+11=0 intersect at the point (3,4),fi

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