{1641x-8359y=28359 {8359x-1641y=21641 用2元1次方程组的加减法

z1x2c3v4b5002022-10-04 11:39:541条回答

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1641x-8359y=28359 (1)
8359x-1641y=21641 (2)
(1)*8359:
13717119x-69872881y=237052881 (3)
(2)*1641:
13717119x-2692881y=35512881 (4)
(4)-(3):
(69872881-2692881)y=35512881-237052881
66280000y=-201540000
y=-10077/3314
1年前

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