air segment什么意思

英语翻译
Felzenswalb and Huttenlocher[8]described image segmentation based on pairwise region comparison.The algorithm makes simple greedy decisions and produces segmentations that obey the global properties of being not too coarse and not too fine according to a particular region comparison function.The method is time linear in the number of graph edges and is fast in practice.

有一道微机原理的题,
已知程序的数据段为：
DATA SEGMENT
A DB 'A',10H
B DB 'COMPUTER'
C DW 1234H,OFFH
D DB 5DUP(?)
E DD 1200459AH
DATA ENDS
下列程序执行后,每条指令后的寄存器的内容是什么?
MOV AL,A ;AL=?
MOV DX,C ;DX=?
XCHG DL,A ;DL=?
MOV BX,OFFSET B ;BX=?
MOV CX,3[BX] ;CX=?
LEA BX,D ;BX=?
LES DI,E ;ES=?
LDS SI,E ;SI=?

Transmembrane segment 7 of human P-glycoprotein forms part of the drug-binding pocket帮忙翻译

英语翻译
The upscale cruise sector or luxury segment is the fastes growing segment of the cruise market,with an increasing number in the 50+ age bracket taking luxury cruises.This market sector is af uent and a highly desirable passenger willing to pay for service and prepared to spend,while demanding value.

A large segment of the public against the new tax.这句话正确吗?若不对,如何改正?

英语翻译
If the length of the segment AB is 1,M is the midpoint of the segment AB,and point C divides the segment MB into two parts such that MC:CB=1:2,then the length of AC is

Randomly cut a line segment into three pieces.What is the probability that these three pieces can form a triangle?
随机地将一直线段分成三段.这三段可以形成三角形的概率为多大？

#include
#include
int page(int A,int L );
int Segment(int sn,int sl);
int SegPagt(int sn,int pn,int pd);
typedef struct segtable
{
int segf[256];
int segl[256];
}segtable;
struct segtable st;
typedef struct segpagt
{
int segf[256];
int segl[256];
int ptl[256];
int pt[256];
int pf[256];
int pl;
}segpagt;
struct segpagt sp;
int main()
{
int code;
int pl,pa,sn,sd,pd,pn;
//const int ptl ;
int temp;
do{
printf("----------------地址换算过程----------------------------nn");
printf(" 1.分页式地址换算n");
printf(" 2.分段式地址换算n");
printf(" 3.段页式地址换算n");
printf(" 4.结束运行nn");
printf("----------------------------------------------------------n");
printf("请输入您的选择：");
scanf("%d",&code);
switch(code)
{
case 1:{
printf("注意:请演示设定页表长度小于n");
printf("请输入换算的逻辑地址：n");
scanf("%d",&pa);
printf("页面大小（B）:n");
scanf("%d",&pl);
page(pa,pl);
}break;
case 2:{
printf("请演示设定段表长度小于n");
printf("请输入逻辑地址的段号:n");
scanf("%d",&sn);
printf("段内地址:n");
scanf("%d",&sd);
Segment(sn,sd);
}break;
case 3:{
printf("预设定段表长为,页面大小为n");
printf("请输入逻辑地址的段号:n");
scanf("%d",&sn);
printf("页号:n");
scanf("%d",&pn);
printf("页内地址:n");
scanf("%d",&pd);
SegPagt(sn,pn,pd);
}break;
case 4:{}break;
}
}while (code

SEGMENT TOO LARGE 错误
C51 COMPILER V6.23a - SN:K1RIP-M2192E
COPYRIGHT KEIL ELEKTRONIK GmbH 1987 - 2002
C51 COMPILATION COMPLETE.0 WARNING(S),1 ERROR(S)
ERROR C249 IN LINE 92 OF CHESHI1.C:'DATA':SEGMENT TOO LARGE
编译/汇编过程中发现错误.
汇编/编译发现错误!终止!
#include
sbit dir=P1^0;
sbit rl=P1^1;
sbit ll=P1^2;
sbit cp=P2^7;
sbit h1=P1^3;
sbit h2=P1^4;
sbit l1=P1^5;
sbit l2=P1^6;
sbit l3=P1^7;
sbit l4=P2^0;
sbit sb1=P2^1;//开始
sbit sb2=P2^2;//待机
sbit sb3=P2^3;//正
sbit sb4=P2^4;//反
sbit sb5=P2^5;//+
sbit sb6=P2^6;//-
#define dat P0
unsigned char a[][16]=
{
0x08,0x18,0xC8,0x14,0x32,0x11,0xE8,0x08,0x0C,0xEA,0x08,0x88,0x88,0x08,0x08,0x08,
0x02,0x02,0x3F,0x02,0x02,0x02,0x7F,0x08,0x08,0x7F,0x08,0x08,0x08,0x08,0x0A,0x04,/*"待",0*/
0x08,0x08,0x08,0x7F,0x08,0x08,0x1C,0x2C,0x2A,0x0A,0x89,0x88,0x48,0x48,0x28,0x08,
0x00,0x1F,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x10,0x50,0x50,0x50,0x60,0x00,/*"机",1*/
};
unsigned char b[][16]=
{
0x00,0xFE,0x00,0x00,0x00,0x00,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0xFF,0x00,0x00,
0x00,0x7F,0x01,0x01,0x01,0x01,0x01,0x3F,0x01,0x01,0x01,0x01,0x01,0x7F,0x00,0x00,/*"正",0*/
0x00,0xFC,0x04,0x04,0xFC,0x14,0x14,0x24,0x24,0x44,0x84,0x84,0x42,0x32,0x0D,0x00,
0x1E,0x01,0x00,0x00,0x0F,0x08,0x08,0x04,0x04,0x02,0x01,0x01,0x06,0x38,0x10,0x00,/*"反",1*/
};
unsigned char c[][16]=
{
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x42,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"0",0*/
0x00,0x00,0x00,0x08,0x0E,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x3E,0x00,0x00,/*"1",1*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x20,0x20,0x10,0x08,0x04,0x42,0x7E,0x00,0x00,/*"2",2*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x20,0x18,0x20,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"3",3*/
0x00,0x00,0x00,0x20,0x30,0x28,0x24,0x24,0x22,0x22,0x7E,0x20,0x20,0x78,0x00,0x00,/*"4",4*/
0x00,0x00,0x00,0x7E,0x02,0x02,0x02,0x1A,0x26,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"5",5*/
0x00,0x00,0x00,0x38,0x24,0x02,0x02,0x1A,0x26,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"6",6*/
0x00,0x00,0x00,0x7E,0x22,0x22,0x10,0x10,0x08,0x08,0x08,0x08,0x08,0x08,0x00,0x00,/*"7",7*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x24,0x18,0x24,0x42,0x42,0x42,0x3C,0x00,0x00,/*"8",8*/
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x64,0x58,0x40,0x40,0x24,0x1C,0x00,0x00,/*"9",9*/
};
void delay(int i)
{
int a,s;
for(a=0;a

PETS/SAT (0016)
Segment AB is perpendicular to segment BD.
Segment AB and segment CD bisect each other at point X.
If AB = 8 and CD = 10, what is the length of BD ?

请教contribution margin 与segment margin
除了金山的翻译，在财务上怎么解释？

想知道:昆明市no.4-12,s segment of century city,guangfu roard,kunming,yunnan province在哪?

英语翻译
What is the length of the longest line segment that can be drawn joining any two points in the array without passing through any other point

1.the equation of the perpendicular bisector of the segment joining the points whose coordinates are (1.4)and (-2.3) is
2.if the graph of πx+根号2y+根号3=0 is perpendicular to the graph of ax+3y+2=0 ,the a=

本人新手求高人解释程序
DATA SEGMENT
ORG 32H
DA_WD DW 20H
NUM1 = 10*10
NUM2 EQU 70H
REL1 DW NUM1 LE NUM2
REL2 DB NUM1 NE NUM2,NUM1 EQ NUM2
NUM3 EQU 945H
NUM4 = 35*35
ADRR DW REL1,9873H,REL2
DATA ENDS
COSEG SEGMENT
ASSUME CS:COSEG,DS:DATA
BEGIN:MOV AX,DATA
MOV DS,AX
MOV AX,DA_WD+1
；(AX)=
①
MOV BX,OFFSET DA_WD
；(BX)=
②
MOV CL,HIGH(OFFSET REL2)
MOV CH,TYPE DA_WD
；(CX)=
③
MOV DX,REL1
；(DX)=
④
MOV AX,WORD PTR REL2
；(AX)=
⑤
MOV BX,NUM4 LE NUM3
；(BX)=
⑥
MOV CX,NUM4 GT NUM3
；(CX)=
⑦
MOV DX,ADRR+1
；(DX)=
⑧
LEA SI,ADRR+1
；(SI)=
⑨
MOV AH,4CH
INT 21H
COSEG ENDS
END BEGIN

As shown in figure 1,point C is on the segment BG and quadrilateral ABCD is a square.AG intersects BD and CD at points E and F,respectively.If AE=5 and EF=3,then FG=( )

Segment Base Length
0 219 600
1 2300 14
2 90 100
3 1327 580
4 1952 96
What are the physical addresses for the following logical addresses?
a.0,430
b.1,10
c.2,500
d.3,400
e.4,112
并麻烦 讲解下 急等!
segment 对应 01234
base 对应 219 2300 90 1327 1952

VS2010上没有问题,交上去一直Runtime Error(Segment Fault),求指导
代码：
#include
#include
#include
int main()
{
char s[20],line[205],last[10];
int len,i;
while(1)
{
scanf("%s",s);
fflush(stdin);
if(!strcmp(s,"ENDOFINPUT")) break;
//scanf("%[^n]s",line);
gets(line);
fflush(stdin);
scanf("%s",last);
fflush(stdin);
len=strlen(line);
for(i=0;i='A'&&line[i]='F')
{
line[i]-=5;
}
else
{
line[i]=line[i]-4+'Z'-'A';
}
}
}
printf("%sn",line);
}
return 0;
}
Description
Julius Caesar lived in a time of danger and
intrigue.The hardest situation Caesar ever faced was keeping himself
alive.In order for him to survive,he decided to create one of the
first ciphers.This cipher was so incredibly sound,that no one could
figure it out without knowing how it worked.
You are a sub captain of Caesar's army.It is your job to decipher the
messages sent by Caesar and provide to your general.The code is simple.
For each letter in a plaintext message,you shift it five places to the
right to create the secure message (i.e.,if the letter is 'A',the
cipher text would be 'F').Since you are creating plain text out of
Caesar's messages,you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher.Any non-alphabetical character
should remain the same,and all alphabetical characters will be upper
case.
Input
Input to this problem will consist of a
(non-empty) series of up to 100 data sets.Each data set will be
formatted according to the following description,and there will be no
blank lines separating data sets.All characters will be uppercase.
A single data set has 3 components:
Start line - A single line,"START"
Cipher message - A single line containing from one to two hundred
characters,inclusive,comprising a single message from Caesar
End line - A single line,"END"
Following the final data set will be a single line,"ENDOFINPUT".
Output
For each data set,there will be exactly one line of output.This is the original message by Caesar.

问一道英语数学题的翻译!
A network with n points and a segment joining each point to every other point is called a complete network of size n. If k is the number of segments in a complete netwiork of size n, which of the following is the number of segments in a complete network of size n+1?

Life is a line segment,the intersection after the separation.汉译是什么?

英语翻译
A 1 cm long segment of sciatic nerve was then resected at the site just proximal to the division of tibial and common peroneal nerves,and the incision sites were then closed.机器翻的自己走.

请教segment revenue什么意思
在公司年报里面,好像是某年全年利润,但不是很肯定,原文如下：
Record Pro Forma Adjusted Reportable Segment Revenues and Pro Forma Adjusted Economic Net Income for the full year 2007 of $3.12 billion and $2.12 billion,respectively; $1.62 per adjusted unit after tax

有数据段如下：DATA SEGMENT ORG 10H CONT1 EQU 20H BUF1 DW 300H,0AFH COUNT2 EQU $-BUF1
BUF2 DB 'ASDFG'
DATA ENDS
试问（1）BUF1和BUF2的偏移地址分别是多少?
（2）count的值是多少?
（3）指出单元BUF2+2的内容是多少?

英语翻译
我们的钻头分为两种,一种是镶块的,可以提供单独的segment价格;另一种是烧结的,是一个整体,segment与下面的钢体是连接在一起烧制的,无法拆分,而且拆分后也无法使用.所以不能提供单独的segment价格.与镶块的钻头相比,烧结的在工艺上更复杂,性能更好,使用寿命更长,所以价格更贵一些.您以前购买的钻头可能都是镶块的,所以您会有这方面的疑问.我们是这方面最大的生产企业,相信您在其他方面也有所了解,不会在价格上欺骗您,希望你相信我们.

英语翻译
4 sets of 5-25 reps per segment...（always breath in during stretch,breathe out during flex）

哪位好心人帮俺翻下几何的英文
Segment Area
Segment Height ED
Total Circle Area
Circle Sector, Segment

State the coordinates of the endpoints of a line segment that intersects the y-axis.端点坐标轴

用小于直径的弦切割圆
如题,用小于直径的弦切割一个圆,小的那块区域叫神马?
我一时想不起了,我知道英文叫segment.但不叫chord也不叫sector.
要分的速度>>>>>>>>>

DATA SEGMENT A DB -1,3,2,-2 B DW 5,2,1 DATA ENDS ... LEA BX.B+2 MOV AX,[BX] (AX)=___,(BX)=__
汇编题目高手们求答案

英语翻译
1.E-book are by far the fastest-growing segment of the otherwise sluggish,recession-plagued publishing business.我翻的：电子书目前为止是发展最快的部分.,出版业在衰退.
of the otherwise sluggish这句怎么翻到里面去请问,单词都明白,但句子理解不了,