几道八下英语题目五一那天我女儿和我在水上乐园玩得真高兴.My daughter and I _____ _____ __

windflower492022-10-04 11:39:541条回答

几道八下英语题目
五一那天我女儿和我在水上乐园玩得真高兴.
My daughter and I _____ _____ _____ _____in the water park last May Day.
Tina去过上海3次
Tina has been to shanghai _____ _____

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阿梅CD 共回答了14个问题 | 采纳率92.9%
五一那天我女儿和我在水上乐园玩得真高兴.My daughter and I (had) (a) (good) (time) in the water park last May Day.Tina去过上海3次 Tina has been to shanghai (three) (times).
1年前

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1.Do you want to____the football team?
A.take part in B.join C.join in D.take up
答案:B
join 指参加某一个团队、机构或者组织并成为其中的一员.而take part in 通常指参加活动、比赛等.
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问几道八下第一章的数学题1.如图,架在消防车上的云梯AB长15m,AD:BD=1 :0.6,云梯底部离地面的距离BC为2
问几道八下第一章的数学题
1.如图,架在消防车上的云梯AB长15m,AD:BD=1 :0.6,云梯底部离地面的距离BC为2m.你能求出云梯的顶端离地面的距离AE吗?(详细解答过程)(浙教版八下数学书P11节前语)
2.若a√2/a+2√a/2+√18a=10.试求a的值.
3.化简1/6x√18x-x^2√1/2x得?
4.√b/2-√8b=
5.计算:1/ab√9ab^3-2√b/a,且a>0,b>0
6.计算:1/(1+√3)+1/(√3+√5)+1/(√5+√7)+…+1/(√623+√625)
以上几题均需要有完整过程并正确才给分.
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1.
按照三角型来算
AD^2+BD^2=AB^2
AB=15; AB^2 = 225
BD = 0.6AD 因为 AD/BD = 1/0.6
AD^2 + (.6AD)^2 = 225m
AD^2 + .36AD^2 = 225m
1.36AD^2 = 225m
AD = 12.86m
DE = BC = 2m
AE = AD + DE = 14.86m
因无图,只是臆测AB,BD,AD是直角三角形,然后DE为地面到D的距离,与BC平行相等.
2.
我猜根号包含(2/a)、(a/2)和(18a)
因为我不知道根号怎么打,将以^(1/2),意为的二分之一次方来表达平方根
a(2/a)^(1/2) = (2a)^(1/2)
2(a/2)^(1/2) = (2a)^(1/2)
(18a)^(1/2) = (9)^(1/2) * (2a))^(1/2) = 3(2a)^(1/2)
和则为:5(2a)^(1/2) = 10
(2a)^(1/2) = 2 平方等号左右边,得
2a = 4, a = 2
3.
晕,请你下次必定加入括号
猜为 1/6 * x * (18x)^(1/2) - x^2 * (1/2x)^(1/2)
1/6 * x * (18x)^(1/2) = (18/36 * x^3))^(1/2) = (1/2 * x^3)^(1/2), x 进根号时变为x^2
x^2 * (1/2x)^(1/2) = (1/2 * x^4/x)^(1/2) = (1/2 * x^3)^(1/2)
两式相等,所以左减右为零.
4.
(b/2)^(1/2) - (8b)^(1/2)
(8b)^(1/2) = (16 * b/2)^(1/2) = 4(b/2)^(1/2)
(b/2)^(1/2) - 4(b/2)^(1/2) = -3(b/2)^(1/2)
5.
同3.
ab 进根号变为 (ab)^2 = a^2 * b^2
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3(b/a)^(1/2) - 2(b/a)^(1/2) = (b/a)^(1/2)
6.
最后这题有点变态
计算机给的答是12
可以用已知方程式(a+b)(a-b) = a^2-b^2来求答
例1/(1+√3) = (1-√3)/(1-3) = (1-√3)/(-2)
同样,后面的步骤变为
(√(2x-1) - √(2x+1))/(-2)
相加所有数,则为
(1-√625)/(-2)中间的全部都自动消掉
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有几道八下的数学题目,浙教版的数学同步练习6.4(1)后面几题,天才进来
有几道八下的数学题目,浙教版的数学同步练习6.4(1)后面几题,天才进来
第一题:在梯形ABCD中,对角线AC与BD互相垂直,且AC=8,BD=6则该体形的高为?
第二题:如图1,在等腰梯形ABCD中,AB∥CD,∠A=60°,CD=CB,点E,F分别在线段AD,CD上,且AE=DF,CE=DF,CE,BF交与点P,则∠BPE的度数为?
第三题:如图2,在梯形ABCD中,AB∥CD,∠A+∠B=90°,E,F分别为AB.CD中点,试探索EF,AB,CD之间的关系.
第四题,如图3,在梯形ABCD中,AB∥CD,DE⊥AB,垂足为E.已知:DE=12,AC=15,BD=20,求梯形ABCD的面积.
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1
令梯形高h
过D做DP//AC交BC延长线于P,AD//BC
所以DP=AC=8,
AC⊥BD,所以DP⊥BD
BP=10
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几道八下英语题,求英语学霸解答谢谢!
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Unit 1
Inviting
Dream
Afford
Pity
Prize
Make up
Called
Go on
Kinds of
Competition
Speaking
Before
Trying
In
Has also
First prize ; writing competition
Haven’t had
Used to join
Don’t have to
Unit 2
Germany
Queen
France
Tower
King
Ancient
On
Arabic
Mix
count
moved
eating
to skate
to get
haven seen
count down
is different from
has been to
so far
for example
有几道八下的数学题目,浙教版的数学同步练习6.4(1)后面几题,天才进来
有几道八下的数学题目,浙教版的数学同步练习6.4(1)后面几题,天才进来
第一题:在梯形ABCD中,对角线AC与BD互相垂直,且AC=8,BD=6则该体形的高为?
第二题:如图1,在等腰梯形ABCD中,AB∥CD,∠A=60°,CD=CB,点E,F分别在线段AD,CD上,且AE=DF,CE=DF,CE,BF交与点P,则∠BPE的度数为?
第三题:如图2,在梯形ABCD中,AB∥CD,∠A+∠B=90°,E,F分别为AB.CD中点,试探索EF,AB,CD之间的关系.
第四题,如图3,在梯形ABCD中,AB∥CD,DE⊥AB,垂足为E.已知:DE=12,AC=15,BD=20,求梯形ABCD的面积.
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3
EF=(AB-CD)/2.
过F作FM平行AD交AB于M,FN平行BC交AB于N.(下面简单地说一下)
AM=DF=CF=BN,AE=BE,所以,EM=EN
∠A=∠FME,∠B=∠FNE.因为,∠A+∠B=90°,所以,∠FME+∠FNE=90°.
三角形MFN为直角三角形,FE是斜边的中线,所以,EF=MN/2.
EF=(AB-AM-BN)/2=(AB-DF-CF)/2=(AB-CD)/2.
几道八下英语题1.I need some money to buy a bike?(改为一般疑问句)2.Why don'
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