Let C be a symmetric matrix of rank one.Prove that C must ha

powelliang2022-10-04 11:39:542条回答

Let C be a symmetric matrix of rank one.Prove that C must have the form C=aww^T,where a is a scalar and w is a vector of norm one.
翻译:C是一个秩为1的对称矩阵.证明C一定有这样的形式:C=aww^T,a是一个常数,w是模为1的向量.

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飞天硕鼠 共回答了23个问题 | 采纳率95.7%
一个外国的数学论坛上有这个问题的答案,如果看不懂,
1年前
jinyan0711 共回答了230个问题 | 采纳率
C的秩为1,则C的列中至少有一列非零,记此列为c,
其余各列皆是c的倍数,即ci=bi*c,1<=i<=n,其中ci是C的第i列,bi是一个数。
于是记b=(b1,b2,...,bn),则C=cb^T。将c单位化后的向量记为u,b单位化向量记为v,
则C=suv^T,s是某个常数。
由于C是对称阵,则auv^T=avu^T,等式两边右乘u后得到
(av^Tu...
1年前

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奇数阶反对称矩阵应该是奇异的(或退化的)
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