分式子通分*((x^2-2x+1)/(x^2-1))/((x-1)/(x^2+x))*(4/(a+2))+a-2+a-2

oa5mg7b2022-10-04 11:39:542条回答

分式子通分
*((x^2-2x+1)/(x^2-1))/((x-1)/(x^2+x))
*(4/(a+2))+a-2
+a-2
[(a+2)(a-2)/(a+2)]

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共2条回复
肥猪唛 共回答了18个问题 | 采纳率88.9%
(1)[(x^2-2x+1)/(x^2-1)]/[(x-1)/(x^2+x)]
=(x-1)^2/[(x+1)(x-1)]*{[x(x+1)]/(x-1)}
=(x-1)/(x-1)*x
=x
(2)[4/(a+2)]+a-2
=[4/(a+2)]+[(a+2)(a-2)/(a+2)]
=a^2/(a+2)
1年前
rommel_zhao 共回答了2个问题 | 采纳率
(1) X
(2) a^2/(a+2)
1年前

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