how to graph inequality in the coordinate plane

gdsdxf2022-10-04 11:39:541条回答

how to graph inequality in the coordinate plane
8>y-2x>-4
12>3x-y>-6

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悲伤翻篇 共回答了19个问题 | 采纳率94.7%
20>x>-10
48>y>-24
1年前

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【数学】不等式
equivalent [i'kwivələnt]
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∵a<b<0,
∴设a=-2,b=-1,
A、∵[1/a]=-[1/2],[1/b]=-1,∵-[1/2]>-1,∴[1/a]>[1/b],故本选项错误;
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点评:
本题考点: 不等式的性质.

考点点评: 本题考查的是不等式的基本性质,在解答此类问题时利用取特殊值法求解可以简化计算.

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A.
1
a
1
b
B.
1
|a|
1
|b|
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a-b
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a
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a
) 2
(a+
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∵a<b<0,
∴设a=-2,b=-1,
A、∵
1
a =-
1
2 ,
1
b =-1,∵-
1
2 >-1,∴
1
a >
1
b ,故本选项错误;
B、∵
1
|a| =
1
2 ,
1
|b| =1,
1
2 <1,∴
1
|a| <
1
|b| ,故本选项错误;
C、∵
1
a-b =
1
-2+1 =-1,
1
a =-
1
2 ,-1<-
1
2 ,∴
1
a-b <
1
a ,故本选项错误;
D、∵ (b+
1
a ) 2 = (-1+
1
-2 ) 2 =
9
4 , (a+
1
b ) 2 = (-2+
1
-1 ) 2 =9,
9
4 <9,∴ (b+
1
a ) 2 < (a+
1
b ) 2 ,故本选项正确.
故选D.
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