（x^2y/4a)^2 / (-y/2ax)^2 * (-2x/ay)^4

岗仁波钦2022-10-04 11:39:542条回答

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zyxm6666 共回答了17个问题 | 采纳率94.1%: （x^2y/4a)^2 / (-y/2ax)^2 * (-2x/ay)^4
= x^4y^2/16a^2*4a^2x^2/y^2*a^4y^4/16x^4
=a^4x^2y^4/64; 1年前

may365 共回答了49个问题 | 采纳率: （x^2y/4a)^2 / (-y/2ax)^2 * (-2x/ay)^4
= x^4y^2/16a^2*4a^2x^2/y^2*a^4y^4/16x^4
=a^4x^2y^4/64; 1年前

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