若x=100,y=99,求(x-y+4xy/x-y)(x+y-4xy/x+y) 浏览次数:3Q

rossycloud2022-10-04 11:39:542条回答

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heibaozhuzhu 共回答了17个问题 | 采纳率88.2%
(X-y+4xy/x-y)(x+y-4xy/x+y) =[(X-Y)^+4XY/(X-Y)][(X+Y)^-4XY/(X+Y)] =[(X+Y)^/(X-Y)][(X-Y)^/(X+Y)] =(X+Y)(X-Y) =199
求采纳
1年前
vfdrgh 共回答了18个问题 | 采纳率88.9%
(x-y+4xy/x-y)(x+y-4xy/x+y) ={[(x-y)^+4xy]/(x-y)}{[(x+y)^-4xy]/(x+y)} =[(x+y)^/(x-y)][(x-y)^/(x+y)] =(x+y)(x-y) =199
1年前

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由已知得:X-3=0,Y+2=0 解得:X=3,Y=-2,∴原式=[(X-Y)^2+4XY)]/(X-Y)][(X+Y)^2-4XY]/(X+Y) =(X+Y)^2(X-Y)^2/[(X-Y)(X+Y)] =(X+Y)(X-Y) =X^2-Y^2 =9-4 =5.
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原式
={[(x-y)^2+4xy]/(x-y)}{[(x+y)^2-4xy]/x+y}
={[x^2-2xy+y^2+4xy]/(x-y)}{[x^2+2xy+y^2-4xy]/x+y}
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={[(x+y)^2]/(x-y)}{[(x-y)^2]/x+y}=(x+y)(x-y)
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1.x^2/(x-1)-x-1=(x^2-x^2+1)/(x-1)=1/(x-1)
2.(x-y+4xy/x-y)(x+y-4xy/x+y )
=[(x^2-2xy+y^2+4xy)/(x-y)][x^2+2xy+y^2-4xy)/(x+y)]
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由已知得:
X-3=0,
Y+2=0
解得:X=3,Y=-2,
∴原式=[(X-Y)^2+4XY)]/(X-Y)][(X+Y)^2-4XY]/(X+Y)
=(X+Y)^2(X-Y)^2/[(X-Y)(X+Y)]
=(X+Y)(X-Y)
=X^2-Y^2
=9-4
=5.
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原式= [(x-y)^2/(x-y) + 4xy/(x-y)] [(x+y)^2/(x+y) - 4xy/(x+y)]
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(2004•武汉)计算(x-y+[4xy/x−y])(x+y-[4xy/x+y])的结果正确的是(  )
(2004•武汉)计算(x-y+[4xy/x−y])(x+y-[4xy/x+y])的结果正确的是(  )
A.y2-x2
B.x2-y2
C.x2-4y2
D.4x2-y2
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解题思路:先算小括号里的,再算乘法,把分子因式分解,化简即可.

(x-y+[4xy/x−y])(x+y-[4xy/x+y])=[
(x−y)2+4xy
x−y][
(x+y)2−4xy
x+y]=
(x+y)2
x−y•
(x−y)2
x+y=x2-y2
故选B.

点评:
本题考点: 分式的混合运算.

考点点评: 当整式与分式相加减时,一般可以把整式看作分母为1的分式,与其它分式进行通分运算.需注意:(x+y)2-4xy=(x-y)2,(x-y)2+4xy=(x+y)2的应用.

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先化简(x+y-4xy/x+y)(x-y+4xy/x-y)
(x+y-4xy/x+y)(x-y+4xy/x-y)
=[(x-y)^2/(x+y)][(x+y)^2/(x-y)]
=x^2-y^2
其中x=-1 没y 还求不出来
若x=100,y=99,求(x-y+4xy/x-y)(x+y-4xy/x+y)最好把它写在纸上照下来
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(x-y+4xy/x-y)(x+y-4xy/x+y)
是个平方差式.(a+b)(a-b)=a^2-b^2)
(x-(y-4xy/x+y))(x+(y-4xy/x+y))=x^2-(y-4xy/x+y)^2
=100^2-(99-4*99+99)^2=zijisuan
看看题有误吗?