可靠性设计中的平均失效密度则怎么计算啊 给出公式

ACD

最好是再用其他方法进行验证.比如用BCA法.

ABCD

做出电压电流相关性分析,就搞定了.

1、中国航天史上的跨世纪重点工程是规模最大、技术最复杂、安全性和可靠性要求最高的载人航天工程.
2、如果没有阳光,就不会有美丽的花,就不会有鲜活的生命.

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For the possible[1]; design clutch at the same time,maintenance and dependable sex N · m; Tc — clutch from move the equivalent that dish suffer when ascending the resistance
Of the research also have the great significance.Ask for help that clutch the coalescence process the ,should deal resistance the 矩 from the road resistance for suffering of of car car wheel
Of imitate the true model,and can still proceeds car motive the function's analysis was spread by motive with 矩 to move the department conversion to get,N · m; Jn — simplification
Evaluation.Clutch for equivalent from move the dish to turn to move the deal,kg · the m2
According to the dynamics principle,establish the mechanics' model the system's
1 The establishing of dynamics model and key changes to measure of move the differential calculus as follows of square set:
Certain in the clutch lord,from move the dish to whet the stage,its square set is
D ω e

置信水平为1-a的置信区间为
[(X-σ/(根号n)Z(a/2),X+[(X-σ/(根号n)Z(a/2)]
X为算术平均数 a=1-90%=10%
Z(a/2)=?(查表可以知道)
把数据代入得置信区间!
(2)(3)一样!

果一种报警器的可靠性为0.8,那么安装两只这样的报警器能将可靠性提高到多大?
（1-80%）*80%+80%=96%

效度：指测量的真实性、正确性,即该测验与所要测量的目标特征相符合的程度.
信度：指反映测验分数的稳定性的可靠性的指标,指测量的前后一致性程度,只有信度高的测验才能作为一个稳定可靠的测量工具加以应用.
我感觉是效度啊

The primary characteristic is that the design in whole stucture and basic stucture is for the purose of the reliability of the product.
水平有限,只能到这个程度,不好意思.

The optimal allocation of distribution system switches on the nature of the problem is a design and reliability constraints of 0-1 integer programming problems, often based on cost-benefit analysis, the investment in equipment to reduce power losses and overall efficiency obtained by the formation of the objective function, the establishment of model. The model is a nonlinear, non-differentiable, continuous - discrete mixed combinatorial optimization problems. Meanwhile, the decision variables the objective function is not easy to resolve with the expression of its large computational complexity, is a combinatorial optimization problem. There are many ways to solve the current, such as: direct calculation, sub-feeder the simple method, heuristic methods, Bellmann methods, artificial intelligence algorithms. Now more commonly used artificial intelligence algorithms, including simulated annealing, genetic algorithm, immune algorithm, tabu search algorithms, particle swarm algorithm, these algorithms are still to some extent, there is still insufficient. For example, the genetic algorithm itself, the performance characteristics of the defect, making their genetic algorithm to solve practical problems, easy to fall into local optimal solution. PSO is the need to go through more cycles before convergence to the global optimum. In the above stochastic optimization algorithms, due to the dimension of the limit, the optimization process in the distribution system switches each switch position corresponds to a variable, the state quantity, so easily lead to inefficient search. To be more reasonably applied to practical problems in the past, must find a solution both accurate and efficient method. By considering reliability and economic coordination, the optimal configuration of switches range of options; power distribution system for the probability of availability indicators known conditions, solving the optimal solution, in order to achieve practical and effective purpose.

选A。BCD属于会计核算的基本原则。

你所要证明的是测量设备的可靠性,你可以找一下：MSA（Measure System Analysis）,不过需要更多的样本.找你所述,只有一个样本,这样不好做分析.

至少有百分之80 那就是说10个部件里面至少有八个正常 则正常工作部件数目X=8,9,10
p(x=8)=(C8 10)x0.9^8x0.1^2
p(x=9)=(C9 10)x0.9^9x0.1
p(x=10)=0.9^10
则最后概率为P(x=8)+p(x=9)+p(x=10) 由于时间关系 没有算 应该蛮好算的 辛苦码字望采纳~
我是一名高二学生 现在正在学 不知楼主学没学过 这是符合二项分布的题

求一起停止工作时击中仪器的粒子数的数学期望.?
求仪器停止工作时击中仪器的粒子数的数学期望.?
2/((1-0.9^2)+0.2*0.3)=8

整个元件正常工作的事件为A,从图形上来看,有三个类似并联的电路,共有5个小元件,设每个小元件正常工作的事件分别为A1,A2,A3,A4,A5,显然从图中可以看出,如果要事件A发生,只需要三条线路中至少一条正常工作即可,设定三条线路正常工作的事件分别为N1,N2,N3(顺序从上而下）,由事件的性质可知：A=N1+N2+N3,N1=A1A2,N2=A3,N3=A4A5,
所以P(A)=P(N1+N2+N3)=P(N1)+P(N2)+P(N3)-P(N1N2)-P(N2N3)-P(N1N3)+P(N1N2N3)
对于以上概率,我们分别计算P(N1)=P(A1A2)=P(A1)P(A2)=r^2,同理可得P(N2)=r,P(N3)=r^2,P(N1N2)=r^3,P(N2N3)=r^3,P(N1N3)=r^4,P(N1N2N3)=r^5,代入即可求得：P(A)=r^5-r^4-2r^3+2r^2+r
此题关键是事件运算搞清楚,然后就是事件的概率公式运用.不知答案对否,有啥问题,可继续追问

（1）3；沿着斜面将物体拉上去所做功，比直接将物体提升做的功还少
（2）匀速；偏大
（3）用小车做实验时，小车与斜面之间是滚动摩擦，产生的阻力很少可以忽略不计，用木块代替小车时，木块与斜面之间是滑动摩擦，产生的阻力较大，沿斜面方向拉小车的也相应地增加，计算出的“F·s”比“G·h”大得多。

六、生物降解作用
生物降解是引起有机污染物分解的最重要的环境过程之一.水环境中化合物的生物降解依赖于微生物通过酶催化反应分解有机物.当微生物代谢时,一些有机污染物作为食物源提供能量和提供细胞生长所需的碳；另一些有机物,不能作为微生物的唯一碳源和能源,必须由另外的化合物提供.因此,有机物生物降解存在两种代谢模式：生长代谢(Growth metabolism)和共代谢(Cometabolism).这两种代谢特征和降解速率极不相同,下面分别进行讨论.
1．生长代谢
许多有毒物质可以像天然有机化合物那样作为微生物的生长基质.只要用这些有毒物质作为微生物培养的唯一碳源便可鉴定是否属生长代谢.在生长代谢过程中微生物可对有毒物质进行较彻底的降解或矿化,因而是解毒生长基质去毒效应和相当快的生长基质代谢意味着与那些不能用这种方法降解的化合物相比,对环境威胁小.
一个化合物在开始使用之前,必须使微生物群落适应这种化学物质,在野外和室内试验表明,一般需要2—50天的滞后期,一旦微生物群体适应了它,生长基质的降解是相当快的.由于生长基质和生长浓度均随时间而变化,因而其动力学表达式相当复杂.Monod方程是用来描述当化合物作为唯一碳源时,化合物的降解速率：
式中：c——污染物浓度；
B——细菌浓度；
Y——消耗一个单位碳所产生的生物量；
μmax——最大的比生长速率；
Ks——半饱和常数,即在最大比生长速率μmax一半时的基质浓度.
Monod方程式在实验中已成功地应用于唯一碳源的基质转化速率,而不论细菌菌株是单一种还是天然的混合的种群.Paris等用不同来源的菌株,以马拉硫磷作唯一碳源进行生物降解(如图3—34所示).分析菌株生长的情况和马拉硫磷的转化速率,可以得到Monod方程中的各种参数：μmax =0.37h－1,Ks=2.17μmol／L(0.716mg／L),Y=4.1×1010cell／μmol(1.2 ×1011cell／mg)
Monod方程是非线性的,但是在污染物浓度很低时,即Ks>>c,则式可简化为：
－dc／dt=Kb2·B·c’
式中：Kb2——二级生物降解速率常数.
Paris等在实验室内用不同浓度(0.0273—0.33μmol／L)的马拉硫磷进行试验测得速率常数为(2.6±0.7) ×10-12L／(cell·h),而与按上述参数值计算出的μmax/(Y·Ks)值4.16×10-12L／(cell·h)相差一倍,说明可以在浓度很低的情况下建立简化的动力学表达式(3—156).
但是,如果将此式用于广泛的生态系统,理论上是说不通的.在实际环境中并非被研究的化合物是微生物唯一碳源.一个天然微生物群落总是从大量各式各样的有机碎屑物质中获取能量并降解它们.即使当合成的化合物与天然基质的性质相近,连同合成化合物在内是作为一个整体被微生物降解.再者,当微生物量保持不变的情况下使化合物降解,那么Y的概念就失去意义.通常应用简单的一级动力学方程表示：
式中：Kb—一级生物降解速率常数.
2．共代谢
某些有机污染物不能作为微生物的唯一碳源与能源,必须有另外的化合物存在提供微生物碳源或能源时,该有机物才能被降解,这种现象称为共代谢.它在那些难降解的化合物代谢过程中起着重要作用,展示了通过几种微生物的一系列共代谢作用,可使某些特殊有机污染物彻底降解的可能性.微生物共代谢的动力学明显不同于生长代谢的动力学,共代谢没有滞后期,降解速度一般比完全驯化的生长代谢慢.共代谢并不提供微生物体任何能量,不影响种群多少.然而,共代谢速率直接与微生物种群的多少成正比,Paris等描述了微生物催化水解反应的二级速率定律：
由于微生物种群不依赖于共代谢速率,因而生物降解速率常数可以用Kb=Kb2·B表示,从而使其简化为一级动力学方程.
用上述的二级生物降解的速率常数文献值时,需要估计细菌种群的多少,不同技术的细菌计数可能使结果发生高达几个数量级的变化,因此根据用于计算Kb2的同一方法来估计B值是重要的.
总之,影响生物降解的主要因素是有机化合物本身的化学结构和微生物的种类.此外,一些环境因素如温度、pH、反应体系的溶解氧等也能影响生物降解有机物的速率.

理论上残压低对设备的保护性要好点,但实际使用中只要避雷器的残压是在设备能承受范围之内,影响并不大,例如某个设备能够运行瞬间过电压是3000V,那残压是1500V和残压是2000V的避雷器对设备的保护性是没什么区别的.
而可靠性还是看避雷器本身的质量决定.

照葫芦画瓢吧.指示剂它只说了铬黑T,还有用到钙红.测锌和铝的话,大概要换指示剂,不过有表格可以查.
水的总硬度的测定
实验目的
1.了解配位滴定法基本原理和方法.
2.了解水的硬度的概念及其表示方法.
实验原理
含有钙、镁离子的水叫硬水.测定水的总硬度就是测定水中钙、镁离子的总含量,可用EDTA配位滴定法测定：
滴定前：M + EBT M-EBT
(红色)
主反应：M + Y MY
终点时：M-EBT + Y MY + EBT
(红色) （蓝色）
滴定至溶液由红色变为蓝色时,即为终点.
滴定时,Fe3+、Al3+等干扰离子可用三乙醇胺予以掩蔽；Cu2+、Pb2+、Zn2+等重属离子,可用KCN、Na2S或巯基乙酸予以掩蔽.
水的硬度有多种表示方法,本实验要求以每升水中所含Ca2+、Mg2+总量（折算成CaO的质量）表示,单位mg·L-1.
器材和药品
1.器材 天平（0.1g、0.1mg）,容量瓶（100mL）,移液管（20mL）,酸式滴定管（50mL）,锥形瓶（250mL）等.
2.药品 HC1（1∶1）,乙二胺四乙酸二钠（Na2H2Y·2H2O,A.R.）,碱式碳酸镁[Mg（OH）2·4MgCO3·6H2O,基准试剂],NH3-NH4Cl缓冲溶液（pH=10.0）,三乙醇胺（1∶1）,铬黑T指示剂（0.2%氨性乙醇溶液）等.
实验方法
一、Mg2+标准溶液的配制（约0.02mol·L-1）
准确称取碱式碳酸镁基准试剂0.0.25g,置于100mL烧杯中,用少量水润湿,盖上表面皿,慢慢滴加1∶1 HC1使其溶解（约需3~4mL）.加少量水将它稀释,定量地转移至100mL容量瓶中,用水稀释至刻度,摇匀.
其浓度计算：
二、EDTA标准溶液的配制与标定
1.EDTA标准溶液的配制（约0.02mol·L-1）
称取2.0g乙二胺四乙酸二钠（Na2H2Y·2H2O）溶于250mL蒸馏水中,转入聚乙烯塑料瓶中保存.
2.EDTA标准溶液浓度的标定
用20mL移液管移取Mg2+标准溶液于250mL锥形瓶中,加入10mL氨性缓冲溶液和3~4滴EBT指示剂,用0.02mol·L-1EDTA标准溶液滴定,至溶液由紫红色变为蓝色即为终点.平行标定3次.
EDTA浓度计算：,取三次测定的平均值.
三、水的总硬度测定
用20mL移液管移取水样于250mL锥形瓶中,加氨性缓冲溶液6mL,1∶1三乙醇胺溶液3mL,EBT指示剂3~4滴,用EDTA标准溶液滴定,至溶液由紫红色变为蓝色即为终点.平行测定3次.
水的总硬度计算：,取三次测定的平均值.
思考题
1.用EDTA滴定Ca2+、Mg2+时,为什么要加氨性缓冲溶液?
2.测定水的总硬度时,加入三乙醇胺的目的是什么?
3.用HCl分解碱式碳酸镁基准试剂时,不先加水润湿或HCl过浓,会对标定结果产生什么影响?
4.水样中钙含量高而镁含量低时,常在溶液中先加入少量MgY,这样做的目的是什么?为什么?

主要有仪器的准确度与稳定性,是否经过调谐,以及进样量的多少,和物质本身的结构,操作人员手法,和库的本身完善程度.

G sq/Hz,是功率频谱密度的单位,对应的频率下加速度与振幅的积分关系!

设需要用x个报警器并联
1-(1-0.96)^x≥0.9999
0.04^x≤0.0001
x*lg0.04≤lg0.0001
x*(2lg2-2)≤-4
x*(2*0.3010-2)≤-4
-1.3980x≤-4
x≥2.86

需要用3个报警器并联

As an essential structural component ; CCC's reliability is important to AAA which is an important transport tool:However CCC stress concentration areas are fragile as a consequence of poor working envioronment:Depending on the damage condition,
it is possible to use stress analysis and finite element test to dignose the problem and to propose a solution to reduce the fragelity:The new design,tested using finite element analysis,effectively reduces the strees concentration and greatly enhances reliability of product ;

以单元3为中枢单元对系统进行分解,分3正常和失效两种情况计算,原系统的可靠度可以根据全概率公式计算,最终结果可得原系统的可靠度为：
Rs=R3*[1-(1-R1)*(1-R4)]*[1-(1-R2)*(1-R5)]+(1-R3)*[1-(1-R1*R2)*(1-R4*R5)];
希望能帮到你.

说实在的,应该是c吧!

σ已知u的95%置信区间公式
解出最小的n为1537

解:
置信水平为1-a的置信区间为
[(X-σ/(根号n)Z(a/2),X+[(X-σ/(根号n)Z(a/2)]
X为算术平均数 a=1-90%=10% Z(a/2)(查表)
把数据代入得置信区间!
(2)(3)一样!

1.根据被测物选择合适的应变片
2.测点处打磨并用酒精擦拭干净
3.在测点处划好十字线
4.在应变片反面滴上胶水（502等）
5.将应变片立即贴在十字线的中心位置,并用手指隔着薄膜对应变片轻压
6.在应变片旁边用胶水贴上接线端子,将应变片导线焊在接线端子上,注意导线不能与被测物体接触造成短路,最后用导线通过接线端子连上应变仪即可
应变片粘贴的好坏对测试结果起着非常重要的影响,当然首先得选用专业的应变仪,介绍一个靖江泰斯特电子生产的应变仪还不错~

不是的,满意度有3个问题,每个问题假设有5个答案,分别是完全不满意（1分）到完全满意（5分）,三道题目的分数加起来就是满意度.可靠性一样.然后两者就可以进行相关分析了

Along with the rapid economic development, industrialization and urbanization construction acceleration, the power demand is also increasing. The grid power supply ability and reliability of regional development of social economy is extremely important. Substation in power system is one of the indispensable important link, its power conversion and electrical power for the redistribution of heavy tasks, the safety and economical operation of power grids play a pivotal role. The transformer substation design must reflect socialist technology economic policy, conform to the safe and reliable, advanced technology, reasonable economy and ensure quality requirement, in this design fully embodies the these requirements. This thesis mainly is a part of the electrical design instructions, and its content requirements: 1) substation the main electrical wiring design; 2) electricity wiring design; 3) short-circuit current calculation; 4) the main electrical equipment selection; 5) substation electrical general layout; 6) with the relay protection

Railway signal system is to protect the security of rail transport infrastructure.With the development of electronic technology,railway signal IC products to more and more as the core,and its reliability characteristics and the impact of the system has changed fundamentally,so the use of reliability engineering theory to study the reliability of the signal equipment is to protect Railway safety and efficiency of an important means of transport.In this paper,no insulation ZPW-2000A frequency shift orbit to study the reliability of the circuit.ZPW-2000A-type track circuit has been widely used in automatic block system,to ensure that the train has become an important traffic safety infrastructure of railway signals.ZPW-2000A as a result of the French non-UM71 track circuit insulation technology imports,domestic production based on the combination of technical conditions to develop,so given the reliability of indicators is less clear.In this paper,the reliability of the project is therefore to study the theory of ZPW-2000A system reliability,an important research value and significance.This article focuses on the reliability of the system block diagram and fault tree model,combined with "GJB / Z 299B-98 the reliability of electronic equipment is expected to manual," Analysis of the reliability parameters of each module,the reliability of the entire system is expected.Analysis module for the system and the consequences of its failure mode analysis,as the expansion of the fault tree model.In this paper,a theoretical analysis of system reliability,application Riverstone Blue Series software company BlockSim,the establishment of ZPW-2000A system reliability block diagram and fault tree model,the reliability of the parameters of each module is expected to make through to Blocksim simulation,the relevant parameters.N +1 for the transmitter and receiver structure of 0.5 +0.5 simulation.At the same time,modules of the system failure mode and effect analysis,FMEA report form,which as a Fault Tree added and improved.

供电可靠性RS=1-（总停电时户数/总用户数/统计期间总小时数）；
提高供电可靠性就意味着缩短停电时间,减少停电范围,提高企业效益

中国航天史上规模最大、技术最复杂、安全性和可靠性要求最高的跨世纪重点工程是载人航天工程.

解题思路：电炉丝和铜线串联在电路中（通过的电流相等），通电时间是相同的，而电炉丝的电阻比导线的电阻大，据焦耳定律分析回答．

电炉丝和铜线串联，I_电炉丝=I_铜线，通电时间t相同，
∵Q=I²Rt，R_电炉丝＞R_铜线，
∴电流产生的热量：Q_电炉丝＞Q_铜线，
∴电炉丝更热．
故答案为：电炉．

点评：
本题考点： 焦耳定律；串联电路的电流规律．

考点点评： 本题主要考查学生对焦耳定律、串联电路电流关系的了解和掌握，利用好串联电流特点是本题的关键．

Fair value as a brand new measurement methods had been widely used in foreign countries,and has become the development trend of the international accounting.And in the accounting information quality,reliability and correlation is decision of accounting information useful main quality structure,they not only and financial report users and to the specific decisions related,but also the choice of measurement attributes related.Compared with the historical cost information,fair value information is generally has strong correlation,but relatively poor reliability.Therefore,for the reliability of the correlation and weigh the formulation explicit standards or for decision useful features of accounting information quality and reflection of the reconstruction will become to promote fair value accounting practice basic requirement.Fair value has been international hot and difficult problem,since the 1980 s,fair value in the international accounting standards and the countries of the accounting standard system played more and more important role in our country,in some standards also directly or indirectly involved with the fair value,but these standards after coming on stage but became some public companies operation profit means,therefore,the formulation of standards department have to greatly reduce the fair value of the application.But along with the market economy further perfected,the fair value of the use of environment more and more mature,on February 15,2006,promulgated new enterprise accounting standard,and to enable the fair value.This paper it is in this context,first from the definition of fair value,this paper introduces the connotation of the fair value,this paper discusses the characteristics of accounting information quality,which primarily on the two main quality features-reliability and want to care about further analysis.Focusing on the analysis of the fair value in the use of the reality of the reliability of accounting information and relevance of influence,and finally to the historical cost with the contrast of the fair value of this measurement attributes are summarized.

1、环境温度：环境温度过高,会影响微机系统的散热,加速微机内部元件和塑料构件的老化；
2、环境湿度：环境湿度过高,特定情况下会在微机系统内部形成结露,严重的会形成短路烧毁元件；
3、电压：要求电压稳定,电压的大幅度波动,会造成微机内部电器元件过早的老化,严重的会造成主板、电源的稳压部分烧毁；如果频繁出现断电,还会造成硬盘盘片的划伤.
4、摆放位置的固定.一定要放在平整的台面或者地面上,特别是在微机开机的状态下,尽量不要晃动微机机箱.因为微机开机后,普通硬盘内的盘片就会保持高速运转,每分钟7200转吧,一旦这时候发生特别剧烈的晃动,会直接导致硬盘盘片划伤——不论有些硬盘厂商宣传有多么好的防震措施,只要你不是使用固态硬盘而是使用了普通的硬盘,那么这个问题从结构上说就不可能避免.同时,考虑到机箱、电源内部至少还有2个散热风扇在高速转动,在开机状态下避免晃动就更加应该注意了.

只有一个可靠度R只能计算不可靠度Q=1-R,短路和断路各自的概率无从得知.如果知道短路故障率和短路状态下的修复时间、断路故障率和断路状态下的修复时间,才能计算概率：
概率=故障率*修复时间/8760

B

In the digital communication,the channel coding is for reduce theerror rate,enhances code which the digital communication thereliability adopts.The digital signal in the transmission process,the additive noise,the code the string harasses and so on to be ableto produce harms the code.MAX+Plus П is the third generationCPLD/FPGA application development system which Altera Corporationpromotes,its contact surface good,practical is convenient; May usethe many kinds of designs input way establishment design project,maycarry on the function simulation and the succession simulation.Editusing the MAX+Plus П software in graphic editor and the text realizesthe linearity to group the encoded code function,and makes theprofile simulation.

The power source is electronic installation's essential functional module,its performance fit and unfit quality immediate influence to electronic installation's technical performance and reliability.
This article introduced the 25V/1A switching power supply's structure,the principle and the design process and so on.The entire power source by the input circuit,the leveling circuit,the feedback circuit,the overvoltage protection electric circuit,the overflow protection circuit,from restores the electric circuit,the output circuit and so on,but also has the soft start function.The switching power supply has the efficiency to be high,the volume is small,the weight is light,the reliability is high,the load shares and so on easily a series of characteristics.This topic uses the switching mode is the entire bridge all controls the rectification filter,moreover the power source has also utilized the soft switch technology,causes its loss to reduce obviously,the DC-DC transformation use cuts the wave boosted circuit to realize,the structure is simple,the transfer efficiency is high; Selects the small breakover resistance,the high shutter speed P60N06 tube for the switching valve,to select the quick recovery diode rectification,reduces the reverse breakover time,reduces the loss.Has realized the design requirements through the experimental verification electric circuit completely the basic quota,and the DC-DC conversion efficiency achieves 85%.The circuit design also has many insufficiencies,each design target also waits for further enhancing.

把所有用户停电时间相加,然后有几个用户就除以几

其实不一定要说明文准确性的词语,如果你要写说明文的话,我就有几个方法可以用来体现说明文的准确性：1、“举例子”举例子可以准确的说明所要表答的事或物,让读者信服.2、“列数字”准确的数字可以增加读者信服度,提高读者的兴趣.3、“做比较”可以用不同的事或物来作比较,从而达到目的,让读者信服.4、“作假设”作假设可以使读者明白道理,答到写作目的,使读者更加信服.5、“打比方”打比方是用通俗易懂的事或物来像读者说明,使读者信服,从而达到目的.……如果你是要写700字以下的作文的话,用这些方法应该就够了.其是还有：“下定义”、“作荃释”、“模状貌”、……等等.

When any potential or visiable safty risk for equipment operation and equipment relibility was detected,all the maintainece work should be paused and the working crew had to be evacuated to the safe p...

通常把可信性看成一个集合名词,认为它包括安全性、可靠性等属性,但也可将它看成像可靠性和安全性一样的单个名词

选A,用到得是最少必要样本量的公式：n=t*2乘90%乘（1-90%）然后除以5%*2

我想问问我是帮人家签字的(租借合同),私底下我们签订协议不需要付房租费也不需要付任何法律责任.但是我想如果万一法律纠纷了的话,我能拿出来（我们签订的私底下签订的文书协议)当做法律依据吗?也就是说我不需要承担法律责任======可以吗?

Abstract:the reliability of accounting information focuses on the definition of the reliability of accounting,in order to maintain its reliability,must adhere to the other accounting principles.As the international accounting standards on the reliability of the discriminant standard for:"when it without significant error or bias,and can reflect its plans to reflect or the reflect of be depended upon by users to have demonstrated the reliability of information.

表达方式有：记叙（叙述）、说明、议论、抒情、描写.
你这里这两句话运用了叙述和说明这两种表达方式.