某8层综合楼,5米,室外给水管网最低压力0.28MPa,能否直接供水?

可参见93安装电器定额:第二章
人工费=直接费*23%
利润=直接人工费*55%
材料费=定额费*92%
补贴费=直接人工费/11.82*2.5
流动费=直接人工费/11.82*2.4
税金=合计*3.41%
上述综合汇总就是工程总造价!

教学楼
teaching building
足球场
football field;football pitch
综合楼
complex building; general building
厕所 [cè suǒ]
[建] toilet
沙地
sand ground

Room 109,1/F(或：1F/L),Multifunctional/Block(2选1) Building
供参

30÷（120+30）=20％

解题思路：此题属于求一个数比另一个数少百分之几，求节约了百分之几，就是求节约的数量占计划投资的百分之几，由此解答即可．

30÷（120+30）

点评：
本题考点： 百分数的实际应用．

考点点评： 此题属于求一个数比另一个数少百分之几，解答的关键是找出被比的量（作除数），用除法解答．

解题思路：此题属于求一个数比另一个数少百分之几，求节约了百分之几，就是求节约的数量占计划投资的百分之几，由此解答即可．

30÷（120+30）

点评：
本题考点： 百分数的实际应用．

考点点评： 此题属于求一个数比另一个数少百分之几，解答的关键是找出被比的量（作除数），用除法解答．

The design is for the structure design of teaching building in Harbin Normal University , the frame structure. Investigation by imitation of the real building and the architectural design, drawing out the layers of reference to the relevant specification plans, elevations, and profiles. According to the above painting the structural drawings, layout and calculation diagram.
First, in the calculation process to calculate the representative value of the gravity load, lateral stiffness. Shear method and by the bottom of the frame vertical stratification, horizontal level loads to calculate internal forces and drift. Then completed the framework of the transverse horizontal wind load calculation of internal forces and displacements, the calculation results were analyzed to confirm the structure under wind load security. Then determine the structure of the computing unit, using the second moment distribution method under the vertical load calculation of internal forces. After the above calculations, the above data analysis of each set of data, moment to adjust, internal force portfolio. Assemble a group or several groups of the most unfavorable combination of internal forces, including bending, shear and axial force, selecting the corresponding results of the frame beam and column reinforcement design. The situation according to the calculation of reinforcement in the book draw reinforcement chart.

No.16,Building A,Comprehensive Building,Minzhebianmao Market,Tongcheng

①30÷（120+30）；

②15×2-5；

③180×（
1
3 -
1
4 ）；

④1÷（
1
30 +
1
20 ）；
故答案为：30÷（120+30）；15×2-5；180×（
1
3 -
1
4 ）；1÷（
1
30 +
1
20 ）．

Comprehensive Building of Working People's Cultural Palace,LiangLukou,Yuzhong District,Chongqing
就是这样了

B 单位工程施工组织设计

students' dormitory

首先指出,根据《中小学建筑设计规范》5.2.1条小学教学楼不应超过4层.而根据《建筑设计防火规范》8.3.1条4层教学楼是不用设室内消防的.
言归正传,根据你提供的数据,这个建筑不算高层,但是体量比较大,按层高3米计算已经超过5万立方,室外消防用水量应按30升/秒计算（《建筑设计防火规范》表8.8.2-2）,室内消防用水量按规定是15升/秒（《建筑设计防火规范》表8.4.1）,如果室内外消防都只能靠消防水池供水的话,按照规定的一次灭火延续时间按2小时（《建筑设计防火规范》表8.6.3）计,就是：
（30升+15升）*3600秒*2小时/1000升=324立方米
这就是消防水池应该有的容量.
设有供消防车取水的消防水池取水口的消防水池是不带水泵房的,靠消防车自带水泵长时间取水并供水,这个距离是为取水安全考虑的,而有消防水泵房的消防水池可由泵房的水泵通过消防水带自主向消防车供水,所以安全.这个水泵房除外我的理解是：带有消防水泵房的消防取水口距离是不限的.

英语教学楼在综合楼和办公楼中间怎么说?
There is the English teaching building existing between complex building and office building
There exists the English teaching building between comprehensive building and office building
The English teaching building lies between complex building and office building
The English teaching building stands between comprehensive building and office building
The English tteaching building is between between comprehensive building and office building

人工翻译!请查实!
戴家村综合楼位于溧水县城珍珠南路以东,金蛙路以南.由戴家村居民委员会投资新建,南京市设计研究院有限公司设计.溧水工程建设监理有限公司监理.南京市第八建筑安装有限公司承包施工.立面和造型反应了新时代住宅建筑的形式.结构设计部分包括结构选型、结构布置、结构计算等,综合运用PKPM、天正等软件对计算数据进行了验算和调整.
该工程为十二层框架结构商业用房.在本建筑设计中,充分利用了框架结构的优点.建筑高度为49.1m,抗震烈度为7度.
关键字1,商业用房2..框架结构3.抗震烈度
Daijia Cun Multiple–use Building is located in the east of South,Zhenzhu Road and the south of Jinwa Road in LiShui County.It is invested and built by Daijia Cun Residents Committee,while designed by Nanjing Design Institute Co.,Ltd and supervised by Lishui Construction Project Supervision Co.,Ltd.The 8th Nanjing Construction and Installation Co.,Ltd undertakes the project.The facade and model reacts the form of residence architecture in new times.The structural design part includes structure selection,structure layout,structural calculation etc..Also the calculation datas are checked and adjusted by softwares such as PKPM and Tianzheng etc.
This project is 12-layer frame structure for commercial housing.In this architecture design,the advantages of frame structures are made full use.The Building is 49.1 m high and has a seismic intensity of 7.0.
Keywords:1.commercial housing; 2.frame structure 3.seismic intensity

显示18个字时,边空有2个,字宽有18个,字距有17个
设字距为a
那么就有2*2a+18*4a+17a=9.3米
a=0.1米
所以边空0.2米,字宽0.4米,字距0.1米

（1）以综合楼为观测中心，教学楼在综合楼的北偏东60°方向上，根据图中的线段比例尺可得：教学楼到综合楼的实际距离是：4×10=40（米），
答：教学楼在综合楼北偏东60°的方向上，距离是40米．
（2）以教学楼为观测中心，综合楼在教学楼的南偏西60°的方向上，距离仍是40米，
答：综合楼在教学楼南偏西60°的方向上，距离是40米．
故答案为：（1）北；东60；40；（2）南；西60；40．

致远路：——非宁静无以致远,非淡泊无以明志.另外还有理想高远的意思

半径：0.8÷2=0.4（m）
地基孔体积：3.14×0.4的平方×4
= 3.14×0.16×4
=0.5024×4
=2.0096（立方米）
16个：2.0096×16=32.1536（立方米）
请点击【选为满意答案】,有问题可以继续求助我团!

楼梯宽度：1.25m,
中间休息平台宽度=1.25m,
踏步尺寸：270*166mm
每一梯段踏步数：9

设长度为x,则宽为y
y=x-5
周长是：2*x+2*y=2*x+2*（x-5）=50
则x=15cm y=10cm
所以长为15cm 宽为10cm

设字宽x,则边空2x/3,字距x/3；18个字总宽18x,18个字有17个字距,总字距17x/3,边空2个,总空4x/3,则：
18x+17x/3+4x/3=9m；
得x=0.36m=36cm；
边空2x/3=24厘米,字宽36厘米,字距x/3=12厘米.

multifunctional building
多功能楼，这个从功能用途上来说
complex building
综合性的建筑

你的实际功率因数为：2815／根号2815²＋3182²＝0.67
若把功率因数补偿到0.92
则：
tgφ1＝根号1－0.67²／0.67＝0.82
tgφ＝根号1－0.92²/0.92＝0.17
所需补偿电容量＝2815×（0.82－0.17）＝1829.75kvar
由于你的三相负荷严重不平衡,造成中性点偏移,所以要烧毁用电设备.请把负荷尽量搭配平衡.并加粗零线线径,因你的系统属于三相不对称负载,所以三相四线要用一样大小的线径.
至于把功率因数提高到0.92,跟设备利用率无关.如果把补偿设备安装在变压器电源端,由于用电设备所需的无功能量同样需要线路传输,所以线路的损耗不会下降多少.如果要提高电能的利用率,降低线路损耗,则应采取就地补偿.所谓就地补偿,就是根据各个配电单元的实际参数,计算出所需补偿量进行分散补偿,把补偿设备尽量靠近负载端安装,这样才能更有效的提高电能利用率,降低线路损耗.

(6000-2400)÷6000×100℅
=3600÷6000×100℅
=0.6×100℅
=60℅
答：综合楼的实际面积比教学楼实际面积少60℅

解题思路：（1）比原价降低了[1/7]，即现价是原价的1-[1/7]，根据分数除法的意义，原价是24÷（1-[1/7]）元；
（2）实际投资120万元，节约了30万元，则原计划投资120+30万元，根据分数的意义可知，节约了30÷（120+30）×100%；
（3）由于利息=本金×年利率×时间，则到期后的利息是5000×5.2%×1，又还应缴纳5%的利息税，即实得利息的1-5%，则可得税后利息是5000×5.2%×1×（1-5%）元．

①24÷（1-[1/7]）
=24÷
6
7，
=28（元）．
答：原价是28元．

②30÷（120+30）×100%
=30÷150×100%，
=20%．
答：节约了20%．

③5000×5.2%×1×（1-5%）
=260×95%，
=247（元）．
答：可得税后利息247元．

点评：
本题考点： 分数除法应用题；百分数的实际应用；存款利息与纳税相关问题．

考点点评： 完成此类题目要注意分析各题中所给条件，然后列出正确算式．

深圳市南山区高新技术产业园北区清华信息港研发综合楼805室
Room 805,Tsinghua IT Port R&D Center Building,North Area,Hi and New Industrial Park,Nanshan District,Shenzhen,Guangdong,China

Wanye Square is a modernized business centre incorporating large-scale department stores,business offices and apartments.It is constituted by two 14-floor tower buildings,one 29-floor complex building,a podium building and a basement floor.Floors 1 to 4 of the business podium building are used for the purpose of a shopping centre while the two 14-floor tower buildings will serve the purpose of top grade business office accommodation.

科研办公综合楼
Comprehensive Office Building of Scientific Research

30÷（120+30），
=30÷150，
=20%；
答：节约了20%．
故答案为：20．

的的

解题思路：由已知条件知道，把计划投资的总钱数看作单位“1”，实际投资的总钱数占计划投资的总钱数的1-15%=85%，是170万元．根据分数除法的意义可求出答案．

170÷（1-15%），
=170÷85%，
=170×[100/85]，
=200（万元）；
答：计划投资200元．
故答案为：200．

点评：
本题考点： 百分数的实际应用．

考点点评： 解此题关键是找到量所对应的分率，然后看单位“1”是已知还是未知，此题未知用除法计算．

75米=7500厘米
32米=3200厘米
图上长:7500×1/200=37.5厘米
图上宽:3200×1/200=16厘米

解题思路：要求种植草皮至少需用多少，就要先求面积，因此可设长方形空地的长为x，则宽=x-5，根据周长公式可列方程：2[x+（x-5）]=50解得x=15则宽为10，根据面积公式可得长方形的面积=10×15=150（平方米）．已知每平方米草皮的种植成本最低是a元．则159平方米到少需要150a元

设长方形长度为x，则2×（x+5+x）=50，
解得：x=10，
则草皮成本价=10×15=150a（元）．
故选C．

点评：
本题考点： 一元一次方程的应用．

考点点评： 此题关键是利用周长公式先求出长与宽，再算出面积，才能算出种植草皮需要的钱．

The Second Phase of Thin-Film Integrated Building Project for Changzhou Jinhai Plastic Company
This design is for the second phase of thin-film integrated building project for Changzhou Jinhai Plastic Company.It’s located in Changzhou city,Jiangsu province.The building has five floors without basement.The first floor is 4.4m high,and the second to fifth floors are 3.3m high.Total height of the building is 17.6m.
It adopts the structure of reinforced concrete frame.Primary conditions and data as below:
1) The building’s secure rate is two.
2) Service longevity of the design is 50 years.
3) Applicable functions of the building are detailed in the construction drawings.
4) This building is located in Changzhou city,Jiangsu province,and the ground roughness is B.
5) The soil type of the ground is type two.
6) The anti-earthquake level of this building is level three.
7) The groundwork level is level two.
8) The fireproof of the building is level two.
9) The geologic condition of this project belongs to stable-ground,no liquefaction.For other geologic conditions,please see the geologic reconnaissance report of this project.

第一题：预算是 150+30=180（万元）所以节约了 30/180=16.7关键是用预算来作为节约的比较值,而不是实际投资.第二题：先算长和宽 （64-8×4）/（4+4）=4（分米）再算整个表面积 4×8×4+2×4×4 = 160 （平方分米...