求解x-1除以x+1小于等于2.

淼cc2022-10-04 11:39:545条回答

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小虾米888888 共回答了25个问题 | 采纳率100%
x等于1
1年前
我来拉拉 共回答了780个问题 | 采纳率
(x-1)/(x+1) ≤ 2
1)x+1<0即x<-1
x-1≥2x+2
x≤-3
所以x≤-3
2)x+1>0 x>-1
x-1≤2x+2
x≥-3
所以x>-1
所以x>-1或 x≤-3
1年前
7262095 共回答了115个问题 | 采纳率
(x-1)/(x+1)≤2
当x+1>0,即x>-1时,
x-1≤2(x+1)=2x+2
x≥-3
所以此时x>-1
当x+1<0,即x<-1时,
x-1≥2(x+1)=2x+2
x≤-3
所以此时x≤-3
综上所述,x≤-3或x>-1
1年前
云中的鸟 共回答了22个问题 | 采纳率
x-1/x+1<=2
x+1>0 有2x+2>=x-1则x>=-3,所以x>-1
x+1<0 则2x+2<=x-1则x<=-3 所以x<=-3
综合看是x>-1或x<=-3
1年前
adkkc 共回答了14个问题 | 采纳率78.6%
1.当X大于-1时:X-1≤2X+2
X-3
得X大于-1
2.当X小于-1时:X-1≥2X+2
X≤-3
得X小于等于-3
1年前

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=abc(a^2+b^2+c^2)-abc(a^2+2bc)
=abc(a^2+b^2+c^2-a^2-2bc)
=abc(b-c)^2
xdy+(y+x^2y^4)dx=0 求解微分方程,
SULARRY1年前2
秋水凡尘 共回答了20个问题 | 采纳率95%
设z=1/y³,则y³=1/z,dy=-y^4dz/3代入原方程得-xy^4dz/3+(y+x²y^4)dx=0==>-xy³dz/3+(1+x²y³)dx=0==>-xdz/(3z)+(1+x²/z)dx=0==>xdz-(z+x²)dx=0==>dz/dx-z/x=x.(1)方程(1)是一...
求解微分方程x(y^2-1)dx+y(x^2-1)dy=0
乃见ww1年前1
lgg829 共回答了15个问题 | 采纳率86.7%
两边乘以1/2,得到的一个恰当微分方程,它是二元函数f(x,y)=(x^2-1)(y^2-1)的全微分,所以,解是:(x^2-1)(y^2-1)=c,c是任意常数.
求解三角函数 cos 2 X (1 - 2 sin ^2 2 X) + cos 4 X ( 1 + cos 2 X)
求解三角函数 cos 2 X (1 - 2 sin ^2 2 X) + cos 4 X ( 1 + cos 2 X)
cos 2 X (1 - 2 sin ^2 2 X) + cos 4 X ( 1 + cos 2 X)
= cos 2 X cos4X (1 + cos 2 X)
= cos 4 X (1 +2cos 2X) = 0
ddand1年前2
丫头片子李 共回答了15个问题 | 采纳率100%
cos 2 X (1 - 2 sin ^2 2 X) + cos 4 X ( 1 + cos 2 X)
cos2xcos4x+cos4x(1+cos2x)=cos4x(1+2cos2x)=2cos4x(cosπ/3+cos2x)
=4cos4xcos(x-π/6)cos(x+π/6)
英文语法问题求解the bicycle was picked up in a small village four hu
英文语法问题求解
the bicycle was picked up in a small village four hundred miles away.这里的four hundred miles away . 在语法中叫什么形式啊起什么作用谢谢.
moyingna1年前1
开心大药房 共回答了14个问题 | 采纳率64.3%
four hundred miles away"四百英里远”,修饰village.因为far不能和具体的数字连用
away 是副词状语,修饰four hundred miles;
four hundred miles away 作为定语修饰a small village 这个地点
利用叠加定理求解电压U,
方块Q1年前1
wcxzyy 共回答了18个问题 | 采纳率83.3%
3A电流源单独作用时 U1=3*[3*6/(3+6)+6*3/(6+3)] = 12V
9V电压源单独作用时 U2=9*6/(3+6) - 9*3/(6+3) = 3 V
U = U1+U2 = 15V
数学求解微分方程xdx=ydy,
联中因1年前3
美丽就是一种心情 共回答了25个问题 | 采纳率84%
xdx=x^2/2
ydy=y^2/2
x=正负y
dL/dy=-0.2/100*L怎么求解L?
yhm_jixuliulang1年前1
终极无间007 共回答了21个问题 | 采纳率85.7%
dL/dy=-0.2/100*L
dL/L=-0.2dy/100
lnL=-0.2/100*y+c1
L=c*e^(-0.2/100y)
初三数学求解 x²-x-4/7=0
踏歌而独行1年前1
233001265 共回答了17个问题 | 采纳率100%
x²-x=4/7
x²-x+1/4=23/28
(x-1/2)²=23/28
x-1/2=±√(23/28)=±√161/14
x=±√161/14+1/2
x=(±√161+7)/14
2X除以2等于24求解
小X色粉丝2号1年前4
会想念的树 共回答了18个问题 | 采纳率88.9%
2X/2=24
2X=24*2
X=24
1=5 2=125 3=425 4=2145 5=? 求解解法
eqy5551年前1
我就他吗日 共回答了15个问题 | 采纳率80%
5=1
这个问题有点骗人,有点思维性,从头再看就发现答案了哦
1=5,反过来,5=1
英语试卷求解1.He( )John and John is his name.A.are B.is C.were D.w
英语试卷求解
1.He( )John and John is his name.A.are B.is C.were D.was
2.The person who teaches you is your( ).A.teach B.teaches C.teacher D.taught
3.The boy studied very( )yesterday.A.hardly B.hard C.tried D.long
4.It is( )cold( )I am unwilling to go out.A.so...that B.not only...but also C.too...to D.not...but
5.If I( )you,I would go.A.were B.was C.am D.are
6.I will try my best( ).A.doing it B.done it C.to do it D.do it
7.The teacher drew a picture( )the blackboard and ask the students to look at it.A.in B.on C.under D.up
8.What can I do( )you?A.to B.for B.with D.as
9.I go to school( )day,except Saturday and Sunday.A.some B.any C.every D.no
10.Look!The car is( )along the street.A.to run B.running C.run D.ran
11.The price of petrol is much (high)now than it was this time last year.
12.His efforts to improve the sales of this product have been very (help).
13.With the (decelop)of foreigh trade,more people are doing import business.
14.He seemed very young,but he was (real)older than all of us.
15.It was (luck)indeed for Mr.Fox to have changed his flight and arrived safe.
依雪凝子5201年前2
宝宝是吗 共回答了16个问题 | 采纳率93.8%
1.B
2.C
3.B
4.A
5.A
6.C
7.B
8.B
9.C
10.B
11.higher
12.helpful
13.developments
14.really
15.lucky
CAPM计算求解The risk-free rate of interest is 2.5%,the covarianc
CAPM计算求解
The risk-free rate of interest is 2.5%,the covariance of returns of P with the market is α(P,M)=0.35 and the standard deviation of the market αm = 2%.The expected return on the market portfplio is 7%.
Calculate the beta and the expected return of P.
月光花瓣1年前1
Jung丫头 共回答了20个问题 | 采纳率95%
β=α(P,M)/(αm)^2
return of P = r + β(return on the market portfplio - r)
r is the risk-free rate of interest.
用你的数据算出的β= 0.35/(2%)^2 = 875 偏大,不符合实际,可能题目给出的数据出现了问题
x^3+4x^2+5x+3=0求解
skylake1年前1
别过分 共回答了17个问题 | 采纳率100%
  三次方程新解法——盛金公式解题法 三次方程应用广泛.用根号解一元三次方程,虽然有著名的卡尔丹公式,并有相应的判别法,但使用卡尔丹公式解题比较复杂,缺乏直观性.范盛金推导出一套直接用a、b、c、d表达的较简明形式的一元三次方程的一般式新求根公式,并建立了新判别法.盛金公式 Shengjin's Formulas 一元三次方程aX^3+bX^2+cX+d=0,(a,b,c,d∈R,且a≠0).重根判别式:A=b^2-3ac;B=bc-9ad;C=c^2-3bd,总判别式:Δ=B^2-4AC.当A=B=0时,盛金公式①:X1=X2=X3=-b/(3a)=-c/b=-3d/c.当Δ=B^2-4AC>0时,盛金公式②:X1=(-b-(Y1)^(1/3)-(Y2)^(1/3))/(3a); X2,X3=(-2b+(Y1)^(1/3)+(Y2)^(1/3))/(6a)±3^(1/2)((Y1)^(1/3)-(Y2)^(1/3))i/(6a),其中Y1,Y2=Ab+3a(-B±(B^2-4AC)^(1/2))/2,i^2=-1.当Δ=B^2-4AC=0时,盛金公式③:X1=-b/a+K;X2=X3=-K/2,其中K=B/A,(A≠0).当Δ=B^2-4AC
求解Anyone breaking the rules will be asked to leave on the sp
求解Anyone breaking the rules will be asked to leave on the spot.中为什么要用breakinq不用breaks?
漂泊yhl1年前3
alienken 共回答了23个问题 | 采纳率82.6%
此处用breaking作定语,限定anyone,句子谓语为will be asked.如要用breaks,则需用定语从句,即who breaks.
英语填空求解1-9
英语填空求解1-9

我不淡定了1年前4
三寸冰 共回答了22个问题 | 采纳率95.5%
求采纳
RT.sin2t(sint+cost)dt求解
RT.sin2t(sint+cost)dt求解
前面那个符号打不出来。
hua1hua2hua31年前1
eily666 共回答了13个问题 | 采纳率76.9%
前面那个符号打不出来.