√3sin2x+cos2x+a =2sin(2x+π/6)+a

84332772022-10-04 11:39:541条回答

√3sin2x+cos2x+a =2sin(2x+π/6)+a
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√3sin2x+cos2x+a =2(√3/2*sin2x+1/2*cos2x)+a
=2(sin2x*cosπ/6+sinπ/6*cos2x)+a
=2sin(2x+π/6)+a
1年前

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