我入住宾馆的时间：7月7号-7月11号.用英文怎么写哇

解题思路：根据题意，可得每个房间至少要配2把钥匙，否则，如果只有1人有某个房间的钥匙，那人恰好不来住店，那么，这个房间就不能打开；所以最少需要钥匙：9×2=18（把），据此解答即可．

根据分析，可得每个房间至少要配2把钥匙，
所以最少需要配钥匙的数量为：
9×2=18（把）．
答：最少需要18把钥匙．

点评：
本题考点： 排列组合．

考点点评： 此题主要考查了排列组合问题的应用，解答此题的关键是判断出：每个房间至少要配2把钥匙．

1 The bed sheet in my room is very dirty,could you replace it?
2 I am a guest just checked in,my room has not been cleaned yet,please rush to my room and clean it!
3 My toilet is broken,can you come over and have a check on it?
4 How come my room does not have any electric kettle while all the other rooms have?

设三人普通房和双人普通房各住了x、y间
依题意，得
解得
答：三人普通房和双人普通房各住了8间、13间。

check-in date, check-out date
国际通用

解题思路：本题可设1楼有x间房，则2楼有x+5间房，再根据题意可列出不等式：4x＜48，5x＞48，且3（x+5）＜48，4（x+5）＞48，再分别计算出x的取值，在数轴上表示出来，看相交的部分有哪些即为答案．

设1楼有x间房，则2楼有x+5间房，
根据题意有：4x＜48，x＜12，
5x＞48，x＞9.6，
且3（x+5）＜48，即x＜11，
4（x+5）＞48，x＞7．
在数轴上可表示为：

所以9.6＜x＜11
因此x=10
答：一楼有10间房．

点评：
本题考点： 一元一次不等式的应用．

考点点评： 本题考查的是一元一次不等式组的运用，解此类题目常常要结合数轴来判断．

解题思路：本题可设1楼有x间房，则2楼有x+5间房，再根据题意可列出不等式：4x＜48，5x＞48，且3（x+5）＜48，4（x+5）＞48，再分别计算出x的取值，在数轴上表示出来，看相交的部分有哪些即为答案．

设1楼有x间房，则2楼有x+5间房，
根据题意有：4x＜48，x＜12，
5x＞48，x＞9.6，
且3（x+5）＜48，即x＜11，
4（x+5）＞48，x＞7．
在数轴上可表示为：

所以9.6＜x＜11
因此x=10
答：一楼有10间房．

点评：
本题考点： 一元一次不等式的应用．

考点点评： 本题考查的是一元一次不等式组的运用，解此类题目常常要结合数轴来判断．

三人间 a 二人间 b
a * 3 + b * 2 = 50
a * 150 + b * 140 < 3000
b = (50-3a)/2
150a + 3500 -210a < 3000
60a > 500
a 是整数,a>8
三人普通间不多于双人普通间
a

解题思路：在有指向标的地图上，要根据指向标的箭头指向北方确定方向．

（1）根据图示：下火车后准备入住白云宾馆应该先乘2路公交车，再换3路公交车到达宾馆；
（2）图上量得AB之间为1.5cm，根据比例尺=[图上距离/实地距离]，计算可得知：AB之间的实地距离为750米；根据指向标，由A到B划船，是从东南到西北方向；
（3）根据指向标，长山公园大门位于体育馆的西北方向．
故答案为：（1）2； 3； （2）750；自东南向西北； （3）西北．

点评：
本题考点： 在地图上表示方向的基本方法及应用．

考点点评： 考查了在有指向标的地图上判定方向，难易适中．

Reside in WEST FENG JING ,fulfill your dream life.
这是外贸的朋友翻译的,英语过八,工作也过八年了,

Book a single room with bath,four double rooms with bath,Check in time is 22 January 2009 to 25,to love you on June 1

123456 is the number of my hotel reservation,I need a bed to provide third adult admission,Extra bed and third adult occupancy expenses I paid at the hotel,besides,Excuse me from JR Osaka to your hotel route,Thank you!

设该宾馆一楼有x间房，则由题意可得不等式组
4x＞48，
4(x-1)

解题思路：本题可设1楼有x间房，则2楼有x+5间房，再根据题意可列出不等式：4x＜48，5x＞48，且3（x+5）＜48，4（x+5）＞48，再分别计算出x的取值，在数轴上表示出来，看相交的部分有哪些即为答案．

设1楼有x间房，则2楼有x+5间房，
根据题意有：4x＜48，x＜12，
5x＞48，x＞9.6，
且3（x+5）＜48，即x＜11，
4（x+5）＞48，x＞7．
在数轴上可表示为：

所以9.6＜x＜11
因此x=10
答：一楼有10间房．

点评：
本题考点： 一元一次不等式的应用．

考点点评： 本题考查的是一元一次不等式组的运用，解此类题目常常要结合数轴来判断．

Dear Sir or Madam,
I’m so grateful for your good service during my stay for BFDU’s pre-test, but I’m writing to ask a favor to find and send back my pack which I left in your hotel.
I checked in on Mar, 2 and out on Mar, 6. Setting off in a rush for the station, I left the pack in Room 606. It’s a blue,  backpack which contains some books that are wanted in reviewing NMET, a red ipod of special edition as well as a credit card. All in the pack matters to me, especially the ipod, a precious gift from my father on my 18 ^th birthday. So much do I cherish it that I feel upset for its loss.
If you find it, would you please post it to me? The return address is on the envelope.
I’ll appreciate it very much if you can give me your earliest reply and thank you for anything you can do for me.
Yours sincerely.
Li Hua

解题思路：本题可设1楼有x间房，则2楼有x+5间房，再根据题意可列出不等式：4x＜48，5x＞48，且3（x+5）＜48，4（x+5）＞48，再分别计算出x的取值，在数轴上表示出来，看相交的部分有哪些即为答案．

设1楼有x间房，则2楼有x+5间房，
根据题意有：4x＜48，x＜12，
5x＞48，x＞9.6，
且3（x+5）＜48，即x＜11，
4（x+5）＞48，x＞7．
在数轴上可表示为：

所以9.6＜x＜11
因此x=10
答：一楼有10间房．

点评：
本题考点： 一元一次不等式的应用．

考点点评： 本题考查的是一元一次不等式组的运用，解此类题目常常要结合数轴来判断．

Dear Helen,
Hi! How is everything going on with you? I’m glad to hear that you are coming to our school and live in a host family. I’m writing this letter to share with you some tips of social communication.
Firstly, remember to shake hands with your host and hostess on your arrival. You’d better greet their family warmly as well. Secondly, it’s important to do a little advance planning if you are going to do some small talk. Have some topics and conversation openers ready. To gaze intently may show your attentiveness, but is not that necessary. The best way is to avoid too much eye contact. Thirdly, if you receive some compliments or gifts from the host, a simple expression of “Thank you” will do. While at dinner, we usually wait for the elders to sit and eat first and don’t forget to take your chance to praise the host for the good cooking.
I hope these ideas will be of great help to you. Look forward to your reply.
Yours sincerely,
Li Hua

设三人普通间共住了X人,则双人普通间住了（50-X）人
根据题意,得150*0.5*X3+140*0.5*(50-X)2=1510
解得X=24,50-X=26
且24、3=8间,26、2=13间
答：三人间普通客房,双人间普通客房各住了8,13间

l am very grateful if you could accept the ABC hotel in the single room for two days?
这句话,主将从现,时态上可以修改下,然后ABC宾馆一间单人房这样写也不太好
可以改为I will be very grateful if you could choose the single room of the ABC hotel to stay for two days!

Dear Mr.JohnIt was a great time durig my trip in Beijing in national holidays.And i had a very comfortable sleep in your Friendship Hotel,However,when i was leaving your hotel the last day 10.6,i noti...

The logistics corporation goes through formalities of moving in for the owner.
如果有什么疑问需要帮助的可以与我QQ联系!

解题思路：6个人拿6把钥匙可以看作是6个人的全排列，而甲乙对门的拿法种数包括甲乙拿301与302门的钥匙，其余4人任意排列，
甲乙拿303与304门的钥匙，其余4人任意排列，甲乙拿305与306门的钥匙，其余4人任意排列，然后利用古典概型概率计算公式求概率．

法一、6个人拿6把钥匙共有
A66种不同的拿法，
记甲、乙恰好对门为事件A，
则事件A包括甲、乙拿了301与302，其余4人随意拿．共
2A44种；
甲、乙拿了303与304，其余4人随意拿．共
2A44种；
甲、乙拿了305与306，其余4人随意拿．共
2A44种；
所以甲、乙两人恰好对门的拿法共有
6A44种．
则甲、乙两人恰好对门的概率为p（A）=

6A44

A66＝
6×4×3×2×1
6×5×4×3×2×1＝
1
5．
故答案为[1/5]．
法二、仅思考甲乙2人那钥匙的情况，
甲可以拿走6个房间中的任意一把钥匙，有6种拿法，乙则从剩余的5把钥匙中那走一把，共有6×5=30种不同的拿法，
而甲乙对门的拿法仅有
3A22＝6种，
所以甲乙恰好对门的概率为p＝
6
30＝
1
5．
故答案为[1/5]．

点评：
本题考点： 古典概型及其概率计算公式．

考点点评： 本题考查了古典概型及其概率计算公式，解答的关键是计算事件种数时做到不重不漏，是基础题．

May I return the accommodation after living for one or two months?If so,may I take my deposit for the rent back?

是
21:22
22:30 45
23:赚,赚505元.
24:

这家旅馆共有x间客房.
4x+19=6x x=9.5
这家旅馆共有10间客房

1楼：9

酒店入住与退房 英语对话
Man:Hi.I have a reservation for tonight,and I just want to check in.
Hotel Clerk:Sure.What's your name?
Man:Uh.Mike Adams.
Hotel Clerk:Okay.Let me check here.Um.Here's your key to open your door.You're in room 360.Just walk down this hall [Okay.],and you'll see the elevators on your right.
Man:Oh,okay,and what time is the restaurant open for breakfast?
Hotel Clerk:It serves breakfast from 6:30-10 a.m.
Man:Oh,okay.And,uh,where's the exercise room?I'd like to,you know,run a couple of miles before going to bed tonight.
Hotel Clerk:It's on the second floor,and it's open til 10 tonight [Okay.],but the treadmill isn't working.
Man:Oh,oh well.And one final question.Do you have wireless Internet in the rooms?
Hotel Clerk:We DO [Ah!]...for $7.95 a night.
Man:Uhhh,I thought something like that would be free.
Hotel Clerk:No,sorry,sir but you can get free wireless access if you sit in the parking lot on the far north side.[Oh!] You see,the hotel next to us has wireless and ....
Man:Oh,great.Um,and uh ...forget that.And every room has a refrigerator,right?
Hotel Clerk:Well,we can have one put in your room for an additional ten dollars a night.
Man:Ahhhh.I thought something like that would be included in the price of the room.
Hotel Clerk:Sorry,sir.
Man:Well,you know,it ...it kind of irks me it when hotels nickel-and-dime their customers like this.I mean,I checked with sev(eral hotels) ...I mean I checked with sev(eral hotels) ...
Hotel Clerk:You really should have checked this one too,shouldn't you have,buddy.
Man:(Laughing) I ...I guest that I ...I'm all flustered now.I mean all the other hotels provide these amenities for free.
Hotel Clerk:Sorry,sir.It's just the way it is at this hotel.
Man:And the bed?Is that extra too?
Hotel Clerk:Of course ...NOT.
Man:Oh.I've had it.I'll just try the hotel across the street.I'm sure they'll give me better service.
Hotel Clerk:Okay,but you'd be canceling your reservation here,so we'll have to charge you a cancellation fee of 50% of the cost of the room.
Man:Ahhhh,forget it.I can't win either way.What's my room again?
Hotel Clerk:Three sixty (360).
Man:Ughhhhhh!

应该是对话吧?
1. We'd like to have two double rooms and a single room, please.
2. How much is that in total? Two double rooms and a single, that's 1,000 yuan in all.
3. When do you plan to leave?
4. How much is that in all if we stay for three days? That will be 300 yuan in all.
5. How much is a double room for one night? It's 100 yuan.
6. How many of you in all? Five.
非常口语化的句子,不能字对字翻译
希望对你有帮助

I may have a need to stay in the university until July or August so that I could finish my thesis for bachelor degree.But offer provides that I should move out before the date of XX.I wonder whether I can prolong my accomodation for one or two months here and what the process is to handle the extention of period.If the accomodation period could not be extended,what should I do next?

You may live in our hotel after checking in .

In accordance with the practice of the United States,when the newly elected president takes office,will choose a puppy with him live in the White House,the dog is also the first American known as the White House dog,the United States in the first dog.
Obama said the selection of pet dogs is not an easy thing,"there are two criteria must be met." Obama's daughters are due to allergies,so this is the first condition for the dog,"low-allergic varieties." Daughter because there is history of allergy.The second requirement:more likely from an animal shelter to adopt stray dogs.Obama also take their own blood cheek:"It is obvious that many of the animal shelter's dog,like me,is mixed."
I think no matter what the final is the only species that look like dogs.Fortunately,the dog is simply too much.

解题思路：设一个单人间需要x元，一个双人间y元，根据入住3个单人间和6个双人间共需1020元，入住1个单人间和5个双人间共需700元可得出方程组，解出即可．

设一个单j间需要x元，一个双j间y元，
由题意得，

3x+cy＝地0口0
x+5y＝200，
解得：

x＝地00
y＝地口0．
则x+y=口口0．
答：入住单j间和双j各地个共需口口0元．

点评：
本题考点： 二元一次方程组的应用．

考点点评： 本题考查了二元一次方程组的应用，属于基础题，解答本题的关键是根据等量关系得出方程组．

四分之一.

若甲进1房(其概率为1/2),则乙应进2房(其概率为1/2) 两概率相乘即为结果1/4.

每家的人数可以看成是他们各自的消耗能力,人多消耗费用多,这是成正比例的.当然,假设每个人消耗能力都一样.则各家每天的消耗能力分别可设成2a,a,2a,a,2a,2a.接下来分别算出各个家庭截止到月底分别入住了多长时间,不难...

酒店GRO欢迎信
Dear General manager xx:
Warmly welcome you to stay at xx Hotel.
We were extremely honored to have the opportunity to serve you as your patronage of our hotel.for any inquiry,please call:60 or 61,we are always at your service.
Thanks for your visit and wish you have a wonderful journey in Huangshan.

1/9

你的水表有问题,不看表的百位数用水量和上面比较也正常
1月入住登记水表是 511吨,
3月底水表显示是 524吨,用水13吨.正常
6月底水表显示是 638吨,（538吨）,用水14吨.正常
可以确定的说没有漏水,
也没有忘记关水龙头.
所以我认为有可能百吨水表出了问题,其他表计应该正常,处理方法：找专业人员打开水表看看是不是表针发生松动造成的.

你可以这么跟他说：“不好意思,我们的客房已经住满了,您方便到其他酒店入住吗?如果不方便的话我们可以为您联系一下附近的酒店,您介不介意去他们酒店入住?我们可以让他们派人来接您.或者你不愿意的话我们可以为您叫好出租车,您可以坐出租车过去,您看这样行吗?”这样一般客人都会同意的.

Dear Guests:
Cool breeze, Tan Kwai fragrance. In the autumn harvest season, I am with all staff sincerely welcome you to stay at our hotel! During your stay, we will be happy to provide you with the best service and the most comfortable environment for you to add fun and warm journey.
Wish you all the best and happy family during National Day.

设：住双人间的人数有X人,则住三人间的人数有50-X人,
则双人间房数是X/2,三人间房数是（50-X）/3
有方程：100*（X/2）+75*（50-X）/3=1900
解得X=22,则双人间房数是22/2=11间,三人间房数是（50-22）/3=6间.
答：该酒店双人间有11间,三人间有6间；是个小酒店.

1
解方程组：
设3人间x间,双人间y间.
3x+2y=50
0.5*（150x+140y）=1510
x=12 y=13
2
题目不够清楚
再来问我

不欢迎，因为他们对外人的要求很高，而且还嘱咐说如果来晚了，山洞就封了。

解题思路：关系式为：3个单人间和6个双人间共需1020元，入住1个单人间和5个双人间共需700元，据此得到一个单人间和一个双人间各需多少钱，进而相加后乘以5即可得到所求．

设一个单人间需要x元，一个双人间需要y元．
由题意得：


3x+6y＝1020①
x+5y＝700②
化简①得：x+2y=340 ③，
②-③得：3y=360，
y=120，
把y=120代入③得：x=100，
∴5（x+y）=1100，
故答案为：1100．

点评：
本题考点： 二元一次方程组的应用．

考点点评： 考查二元一次方程组的应用；找到相应的等量关系求出一个单人间及一个双人间各需多少元是解决本题的关键．

宿舍6间 学生44人 X为宿舍数 Y为学生数 Z为最后一间不空也不满宿舍中的学生数 根据条件可以得出： 4X+20=Y 8X+Z=Y 4X=28-Z X=7-Z/4 因为宿舍肯定为整数，故X得结果值肯定也是整数，且Z是一个大于0小于8的整数 所有得出Z=4，X=6，Y=44 即宿舍6间，学生44人 同学你好，如果问题已解决，记得右上角采纳哦~~~您的采纳是对我的肯定~谢谢哦

小题1:A
小题2:A
小题3:B
小题4:D
小题5:C


小题1:细节理解题，由房卡的欢迎词来得知。“Welcome to Hotel Eiffel”
小题2:细节理解题，此题考查的是旅馆的具体位置，由房卡的路线图可得知。
小题3:由此句可知“Buses to the Hotel:Bus 705, Bus 12, Bus 47”
小题4:理解推断题，故选D.
小题5:理解推断题，选C.

解题思路：本题是一个等可能事件的概率，试验发生所包含的事件是甲和乙随意住进三间空房，每个人都有3种结果，共有3×3种结果，满足条件的事件是甲、乙两人各住一间房的，就是两个人在三个位置进行排列．得到概率．

由题意知本题是一个等可能事件的概率，
试验发生所包含的事件是甲和乙随意住进三间空房，每个人都有3种结果，共有3×3=9种结果，
满足条件的事件是甲、乙两人各住一间房的，就是两个人在三个位置进行排列，共有A₃²=6种结果，
∴甲、乙两人各住一间房的概率是[6/9＝
2
3]，
故答案为：[2/3]

点评：
本题考点： 等可能事件的概率．

考点点评： 本题考查等可能事件的概率，本题解题的关键是理解甲和乙随意住进三间房的意义是每个人都有3种不同的选择，本题是一个基础题．

设住了x个双人间,有2x人
还有50-2x人住三人间,住了(50-2x)/3间
五折优惠
所以三人间150÷2=75元
双人间140÷2=70元
所以一共70x+75(50-2x)/3=1510
70x+1250-50x=1510
20x=260
x=13
(50-2x)/3=8
所以三人间8间,双人间13间