[a²-25/a²+10a+25]÷[a+5/a²-a]×[a²-2a+1/a+

恭喜你,做对了.题目是这个样子,长也没办法了.
[a²-25/a²+10a+25]÷[a+5/a²-a]×[a²-2a+1/a+3]
=[(a+5)(a-5)/(a+5)²]÷[(a+5)/a(a-1)]×[(a-1)²/(a+3)]
=(a-5)/(a+5)×a(a-1)/(a+5)×(a-1)²/(a+3)
=a（a-1）³/（a+5）²（a+3）

[a²-25/a²+10a+25]÷[a+5/a²-a]×[a²-2a+1/a+3]
=[(a+5)(a-5)/(a+5)²]÷[(a+5)/a(a-1)]×[(a-1)²/(a+3)]
=(a-5)/(a+5)÷[(a+5)/a(a-1)]×[(a-1)²/(a+3)]
=[a(a-5)(a-1)/(a+5)²]×[(a-1)²/(a+3)]
=a(a-5)(a-1)³/(a+3)(a+5)²