I want you to like me like Jon on the Garfield

爱你不是一天2022-10-04 11:39:544条回答

I want you to like me like Jon on the Garfield
大家帮我翻译这句话下..

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我上头有银 共回答了23个问题 | 采纳率95.7%
我想你像喜欢加菲猫里的JON一样喜欢我
1年前
就是要等一下 共回答了3个问题 | 采纳率
我要你喜欢我 就像Jon 喜欢garfield一样?
1年前
dadiaocha2008 共回答了27个问题 | 采纳率
我希望你能像Jon喜欢加菲那样喜欢我~~
1年前
wd8607032 共回答了50个问题 | 采纳率
我希望你能像喜欢加菲猫里的JON那样喜欢我。
1年前

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英语写话:假设你是班长,你们班周四下午组织看电影Garfield the movie,请根据下列提示写一篇口头通知,
英语写话:假设你是班长,你们班周四下午组织看电影Garfield the movie,请根据下列提示写一篇口头通知,
假设你是班长,你们班周四下午组织看电影Garfield the movie,请根据下列提示写一篇口头通知,开头和结尾给出.
1.时间:周四下午三点
2.地点:长城电影院
3.电影简介:a movie starred by Garfield,with real actors,Garfield saves a dog friend.
4.集合地点:学校大门口
5.集合时间:2:45 P.M,Thursday
Boys and girl,
Attention please.l have an announcement to make.
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Boys and girl,
Attention please.l have an announcement to make.
At 3 o'clock on Wednesday afternoon, there is a movie starred by Garfield with real actors at Great Wall Theater. It is an exciting movie, in which Garfield saves a dog. Any students interested can get together at the gate of our school at 2.45 pm, on Thursday.
We will go together to the theater for the movie.
急求一篇关于圣诞节和春节中西文化差异的英语小短文,300字左右,只接受发邮箱加分garfield114@163.com
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∵0.5(a+b)(a+b)=2*0.5ab+0.5c2
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∴a2+2ab+b2=2ab+c2,
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图?
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这个很简单
和第8页的差不多,要是用等面积法求解
如图,已知三个角均为直角
∴梯形面积(1)=(上底+下底)×高÷2
=(a+b)(a+b)÷2
梯形面积(2)=½ab+½ab+½c²
∵梯形面积是一定的
∴(a+b)(a+b)÷2=½ab+½ab+½c²
两边都扩大2倍:
(a+b)²=2ab+c²
即a²+2ab+b²=2ab+c²
根据等式的性质
两边都减去2ab
即a²+b²=c²
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伽菲尔德证明勾股定理我做题时看见了一段话:伽菲尔德(Garfield,1881年任美国第二十届总统)利用图一证明了勾股定
伽菲尔德证明勾股定理
我做题时看见了一段话:伽菲尔德(Garfield,1881年任美国第二十届总统)利用图一证明了勾股定理(1876年4月1发表在新英格兰教育日至上)请你试着写出证明过程和公式
图我是画不出来了就请哪位了解这道题的帮帮忙吧
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许多像加菲猫这样卡通动物的气球漂浮在空中.
伽菲尔德( Garfield,1881年任美国第20届总统)利用“三个直角三角形的面积和等于一个直角梯形的面积”(如图所
伽菲尔德( Garfield,1881年任美国第20届总统)利用“三个直角三角形的面积和等于一个直角梯形的面积”(如图所示)证明了勾股定理,请你应用此图证明勾股定理.
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证明:如图,以a,b长为上下底边,以a+b长为高,作梯形ABDE,
即AB⊥BD,ED⊥BD,AB=a,ED=b,在其高BD上再取一点C,使BC=b,连结AC,EC,
在△ABC和△CDE中,


AB=CD
∠B=∠D
BC=DE ,
∴△ABC≌△CDE(SAS),
∴AC=CE,∠BAC=∠DCE,
∴∠ACB+∠DCE=∠ACB+∠BAC=90°,
∴∠ACE=180°-(∠ACB+∠DCE)=180°-90°=90°,
∴△ACE为等腰直角三角形,设AC=c,
由梯形ABDE的面积公式得: S ABDE =
1
2 (AB+ED)⋅BD=
1
2 (a+b)(a+b)=
1
2 (a+b ) 2 ,
梯形ABDE可分成如图所示的三个直角三角形,其面积又可以表示成:S △ABC +S △CDE +S △ACE =
1
2 ab+
1
2 ab+
1
2 c 2 ,

1
2 (a+b ) 2 =
1
2 ab+
1
2 ab+
1
2 c 2 ,
∴a 2 +b 2 =c 2
即在直角△ABC中有a 2 +b 2 =c 2 (勾股定理).
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3.美国第二十任总统伽菲尔德对勾股定理的证明. 如图, S梯形ABCD= (a+b) 2 = (a2+2ab+b2), ① 又S梯形ABCD=S△AED+S△EBC+S△CED = ab+ ba+ c2 = (2ab+c2). ② 比较以上二式,便得 a2+b2=c2.