[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简

pancake_real2022-10-04 11:39:541条回答

[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2) 怎么化简
结果是[(k+1)(k+2)/12][3(k+1)^2+11(k+1)+10] 不过我不知到详细的步骤

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dawnwave 共回答了23个问题 | 采纳率91.3%: 3k^2+11k+10
=（3k+5）(k+2)
[k(k+1)/12](3k^2+11k+10)+(k+1)(k+2)
=[k(k+1)/12]（3k+5）(k+2)+(k+1)(k+2)
=(k+1)(k+2)[k(3k+5)/12+1]
=(k+1)(k+2)[k(3k+5)+12]/12
=(k+1)(k+2)(3k^2+5k+1)/12; 1年前