x²+xy-2y²-x+7y-6

mycelia2022-10-04 11:39:541条回答

x²+xy-2y²-x+7y-6

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原式=(x+2y)(x-y)-x+7y-6
=(x+2y)(x-y)+(2x+4y)-3x+3y-6
=(x+2y)(x-y)+2(x+2y)-3x+3y-6
=(x+2y)(x-y+2)-3(x-y+2)
=(x-y+2)(x+2y-3)
1年前

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