某高级中学有高一、二、三三个年级的学生共1600名,其中高三学生400名,如果通过分层抽样的方法从全体高中学生中抽取一个

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某高级中学有高一、二、三三个年级的学生共1600名,其中高三学生400名,如果通过分层抽样的方法从全体高中学生中抽取一个容量为80人的样本,则应从高三年级学生中抽取的人数是(  )
A.40
B.30
C.20
D.10

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1
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14
20 =
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A.东北→正东→正北
B.正北→东北→西北
C.正北→正东→西北
D.东北→正东→西北
烟花vivian1年前1
doris5678 共回答了10个问题 | 采纳率90%
解题思路:地图上的方向有不同的表示方式.在有指向标的地图上,用指向标指示方向,指向标箭头的指向一般为北向;在有经纬网的地图上,用经纬网定向,纬线指示东西方向,经线指示南北方向;没有指向标与经纬网的地图,通常采用“上北下南,左西右东”的规定确定方向.

在有指向标的地图上,用指向标指示方向,指向标箭头的指向一般为北向;把指向标平移到小明家,根据指向标的箭头指向北方,相反的方向为南方,面对北方右为东左为西,小明去高级中学参加升学考试,应该先往正北走,然后再向东北走,最后再向西北走.因此判定小明行进的方向为正北→东北→西北.
故选:B.

点评:
本题考点: 在地图上表示方向的基本方法及应用.

考点点评: 考查了在有指向标的地图上判定方向的方法,属于基础题.

(8分)某高级中学共有3000名学生,各年级男、女生人数如下表:
(8分)某高级中学共有3000名学生,各年级男、女生人数如下表:

高一
高二
高三
女生
523
x
y
男生
487
490
z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.17.
(1)问高二年级有多少名女生?
(2)现对各年级用分层抽样的方法在全校抽取300名学生,问应在高三年级抽取多少名学生?
avrilzz1年前1
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(1)高二有510个女生;
(2)应在高三抽取99人。

(1)
(2)高三人数y+z=3000-(523+487+490+510)=990
所以应在高三抽取:
答:(1)高二有510个女生;
(2)应在高三抽取99人。
某高级中学共有学生3000名,各年级男、女生人数如下表:
某高级中学共有学生3000名,各年级男、女生人数如下表:
高一年级 高二年级 高三年级
女生 487 x y
男生 513 560 z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.18.
(I)问高二年级有多少名女生?
(II)现对各年级用分层抽样的方法在全校抽取300名学生,问应在高三年级抽取多少名学生?
独自宜人1年前1
pp19831021 共回答了23个问题 | 采纳率95.7%
(1)由
x
3000 =0.18得x=540.所以高二年级有540名女生.…(3分)
(2)高三年级人数为:y+z=3000-(487+513+540+560)=900.

900
3000 ×300=90(人).故应在高三年级抽取90名学生.…(6分)
高中数学集合部分中的一道题!(2)某高级中学高三特长班有100名学生,其中学绘画的学生67人,学音乐的学生45人,而学体
高中数学集合部分中的一道题!
(2)某高级中学高三特长班有100名学生,其中学绘画的学生67人,学音乐的学生45人,而学体育的学生既不能学绘画,又不能学音乐,人数是21人,那么同时学绘画和音乐的学生有多少人?
这样的题如何去思考?
谢谢!
bluexue1年前1
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这样想吧:1. 100-21=79 2. 67+45=112 3. 112-79=33 思路:首先算出学音乐和绘画的总共有79人。再用绘画人数和音乐总人数减去79就得出了。呵呵。你仔细想想吧。你很吝啬,分都不给!
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为了了解某地区高二年级男生的身高情况,从该地区中的一所高级中学里选取容量为60的样本(60名男生的身高,单位:cm),分组情况如下:
分组 151.5~158.5 158.5~165.5 165.5~172.5 172.5~179.5
频数 6 21 m
频率 a 0.1
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某高级中学共有学生2000名,各年级男、女生人数如下表:
某高级中学共有学生2000名,各年级男、女生人数如下表:
高一年级 高二年级 高三年级
女生 373 x y
男生 377 370 z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.19.
(1)求x的值;
(2)现用分层抽样的方法在全校抽取48名学生,问应在高三年级抽取多少名?
(3)已知y≥245,z≥245,求高三年级中女生不比男生多的概率.
阿弥陀佛541491年前1
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解题思路:(1)先根据抽到高二年级女生的概率是0.19,求出高二女生的人数,可求出x值,
(2)再用全校的人数减去高一和高二的人数,得到高三的人数,全校要抽取48人,做出每个个体被抽到的概率,做出高三被抽到的人数.
(3)设出高三年级女生比男生多的事件为A,高三年级女生,男生数记为(y,z),因为y+z=500,且y,z∈N,列举出基本事件空间包含的基本事件有共11个,事件A包含的基本事件数,得到结果.

(1)∵x2000=0.19,∴x=380(2)高三年级人数为y+z=2000-(373+377+380+370)=500现用分层抽样的方法在全校抽取48名学生,应在高三年级抽取的人数为482000×500=12(名).(2)设高三年级女生不比男生多的事件为A...

点评:
本题考点: 列举法计算基本事件数及事件发生的概率;分层抽样方法.

考点点评: 本题考查等可能事件的概率,考查分层抽样,是一个统计的综合题,题目运算量不大,也没有难理解的知识点,是一个基础题.

全回答立即采纳1.某高级中学为每个学生编号,编号设定为6位数,末尾用1表示男生,用2表示女生,如果028432表示202
全回答立即采纳
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2.猫跑2步的路程老鼠要跑10步,而猫跑3步的时间老鼠可以跑4步,猫在老鼠后11米追老鼠,猫最少跑几米才能追上老鼠.算式
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1.015071
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英语翻译最近我刚转入某市的一所高级中学读书,在这个新环境里我遇到了许多问题.希望能得到你的一些建议.
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Recently , I have just turned to a high school in a city. I met lots of problems in this new situation and I hope that I can get some advice from you.
that I can get some advice from you也可以这么表达: that you can kindly give me some advice
英语翻译标题:推荐信尊敬的 你们好!XXX同学在广州市东圃中学(省一级高级中学)就读期间,尊敬老师,关心同学;学习刻苦,
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尊敬的 你们好!
XXX同学在广州市东圃中学(省一级高级中学)就读期间,尊敬老师,关心同学;学习刻苦,善于思考,有专研精神;成绩优良,有进取心;性格稳重,有独立见解,是个有主见的学生,积极参加集体活动,有团结意识,合作精神.有很大的学习潜力,有一股韧劲,相信他会在贵校学有所成.特此推荐,望能批准.
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时间xxx
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你好,以下是比较专业的推荐信写法:
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(2010•嘉定区二模)从某高级中学高一年级的10名优秀学生(其中女生6人,男生4人)中,任选3名学生作为上海世博志愿者
(2010•嘉定区二模)从某高级中学高一年级的10名优秀学生(其中女生6人,男生4人)中,任选3名学生作为上海世博志愿者,问恰好选到2女1男的概率是
[1/2]
[1/2]
.(用数值作答)
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由题意知,本题是一个古典概型,
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而满足条件的事件是恰好选到2女1男,共有C62C41=60种结果,
根据古典概型概率公式得到P=[60/120]=[1/2]
故答案为:[1/2]

点评:
本题考点: 古典概型及其概率计算公式;计数原理的应用.

考点点评: 本题主要考查古典概型,解决古典概型问题时最有效的工具是列举,大纲中要求能通过列举解决古典概型问题,也有一些题目需要借助于排列组合来计数.

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