某高级中学共有学生3000名,各年级男、女生人数如下表:

李晏2022-10-04 11:39:541条回答

某高级中学共有学生3000名,各年级男、女生人数如下表:
高一年级 高二年级 高三年级
女生 487 x y
男生 513 560 z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.18.
(I)问高二年级有多少名女生?
(II)现对各年级用分层抽样的方法在全校抽取300名学生,问应在高三年级抽取多少名学生?

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munanhu 共回答了25个问题 | 采纳率92%
解题思路:(1)先根据抽到高二年级女生的概率[x/3000]=0.18得x=540.从而得出高二年级有多少名女生;
(2)根据表格可知,高三年级人数为:y+z=3000-(487+513+540+560)=900.全校要抽取300人,做出每个个体被抽到的概率,做出高三被抽到的人数.

(1)由[x/3000]=0.18得x=540.所以高二年级有540名女生.…(3分)
(2)高三年级人数为:y+z=3000-(487+513+540+560)=900.
∴[900/3000]×300=90(人).故应在高三年级抽取90名学生.…(6分)

点评:
本题考点: 分层抽样方法;简单随机抽样.

考点点评: 本题考查等可能事件的概率,考查分层抽样,是一个统计的综合题,题目运算量不大,也没有难理解的知识点,是一个基础题.

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5
55 =
1
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(2)设3男生用1、2、3表示,两女生用a、b表示,从5人中取2人担任正副组长的基本事件空间为:
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14
20 =
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解题思路:地图上的方向有不同的表示方式.在有指向标的地图上,用指向标指示方向,指向标箭头的指向一般为北向;在有经纬网的地图上,用经纬网定向,纬线指示东西方向,经线指示南北方向;没有指向标与经纬网的地图,通常采用“上北下南,左西右东”的规定确定方向.

在有指向标的地图上,用指向标指示方向,指向标箭头的指向一般为北向;把指向标平移到小明家,根据指向标的箭头指向北方,相反的方向为南方,面对北方右为东左为西,小明去高级中学参加升学考试,应该先往正北走,然后再向东北走,最后再向西北走.因此判定小明行进的方向为正北→东北→西北.
故选:B.

点评:
本题考点: 在地图上表示方向的基本方法及应用.

考点点评: 考查了在有指向标的地图上判定方向的方法,属于基础题.

(8分)某高级中学共有3000名学生,各年级男、女生人数如下表:
(8分)某高级中学共有3000名学生,各年级男、女生人数如下表:

高一
高二
高三
女生
523
x
y
男生
487
490
z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.17.
(1)问高二年级有多少名女生?
(2)现对各年级用分层抽样的方法在全校抽取300名学生,问应在高三年级抽取多少名学生?
avrilzz1年前1
chkkhc 共回答了22个问题 | 采纳率86.4%
(1)高二有510个女生;
(2)应在高三抽取99人。

(1)
(2)高三人数y+z=3000-(523+487+490+510)=990
所以应在高三抽取:
答:(1)高二有510个女生;
(2)应在高三抽取99人。
某高级中学共有学生3000名,各年级男、女生人数如下表:
某高级中学共有学生3000名,各年级男、女生人数如下表:
高一年级 高二年级 高三年级
女生 487 x y
男生 513 560 z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.18.
(I)问高二年级有多少名女生?
(II)现对各年级用分层抽样的方法在全校抽取300名学生,问应在高三年级抽取多少名学生?
独自宜人1年前1
pp19831021 共回答了23个问题 | 采纳率95.7%
(1)由
x
3000 =0.18得x=540.所以高二年级有540名女生.…(3分)
(2)高三年级人数为:y+z=3000-(487+513+540+560)=900.

900
3000 ×300=90(人).故应在高三年级抽取90名学生.…(6分)
高中数学集合部分中的一道题!(2)某高级中学高三特长班有100名学生,其中学绘画的学生67人,学音乐的学生45人,而学体
高中数学集合部分中的一道题!
(2)某高级中学高三特长班有100名学生,其中学绘画的学生67人,学音乐的学生45人,而学体育的学生既不能学绘画,又不能学音乐,人数是21人,那么同时学绘画和音乐的学生有多少人?
这样的题如何去思考?
谢谢!
bluexue1年前1
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这样想吧:1. 100-21=79 2. 67+45=112 3. 112-79=33 思路:首先算出学音乐和绘画的总共有79人。再用绘画人数和音乐总人数减去79就得出了。呵呵。你仔细想想吧。你很吝啬,分都不给!
某高级中学有高一、二、三三个年级的学生共1600名,其中高三学生400名,如果通过分层抽样的方法从全体高中学生中抽取一个
某高级中学有高一、二、三三个年级的学生共1600名,其中高三学生400名,如果通过分层抽样的方法从全体高中学生中抽取一个容量为80人的样本,则应从高三年级学生中抽取的人数是(  )
A.40
B.30
C.20
D.10
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Honorary certificate
xxx At first,won the first prize in the composition contest.
Administ,as a little encouragement
XX Senior high school
December 2008
为了了解某地区高二年级男生的身高情况,从该地区中的一所高级中学里选取容量为60的样本(60名男生的身高,单位:cm),分
为了了解某地区高二年级男生的身高情况,从该地区中的一所高级中学里选取容量为60的样本(60名男生的身高,单位:cm),分组情况如下:
分组 151.5~158.5 158.5~165.5 165.5~172.5 172.5~179.5
频数 6 21 m
频率 a 0.1
(1)求出表中a,m的值;
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城基的试卷拿不到,其余的到朝霞书店买就有,有08~10的卷
某高级中学共有学生2000名,各年级男、女生人数如下表:
某高级中学共有学生2000名,各年级男、女生人数如下表:
高一年级 高二年级 高三年级
女生 373 x y
男生 377 370 z
已知在全校学生中随机抽取1名,抽到高二年级女生的概率是0.19.
(1)求x的值;
(2)现用分层抽样的方法在全校抽取48名学生,问应在高三年级抽取多少名?
(3)已知y≥245,z≥245,求高三年级中女生不比男生多的概率.
阿弥陀佛541491年前1
错莫过上技院 共回答了16个问题 | 采纳率93.8%
解题思路:(1)先根据抽到高二年级女生的概率是0.19,求出高二女生的人数,可求出x值,
(2)再用全校的人数减去高一和高二的人数,得到高三的人数,全校要抽取48人,做出每个个体被抽到的概率,做出高三被抽到的人数.
(3)设出高三年级女生比男生多的事件为A,高三年级女生,男生数记为(y,z),因为y+z=500,且y,z∈N,列举出基本事件空间包含的基本事件有共11个,事件A包含的基本事件数,得到结果.

(1)∵x2000=0.19,∴x=380(2)高三年级人数为y+z=2000-(373+377+380+370)=500现用分层抽样的方法在全校抽取48名学生,应在高三年级抽取的人数为482000×500=12(名).(2)设高三年级女生不比男生多的事件为A...

点评:
本题考点: 列举法计算基本事件数及事件发生的概率;分层抽样方法.

考点点评: 本题考查等可能事件的概率,考查分层抽样,是一个统计的综合题,题目运算量不大,也没有难理解的知识点,是一个基础题.

全回答立即采纳1.某高级中学为每个学生编号,编号设定为6位数,末尾用1表示男生,用2表示女生,如果028432表示202
全回答立即采纳
1.某高级中学为每个学生编号,编号设定为6位数,末尾用1表示男生,用2表示女生,如果028432表示2022年入学的8班的43号女生,则今年入学的5班7号男生编号是?
2.猫跑2步的路程老鼠要跑10步,而猫跑3步的时间老鼠可以跑4步,猫在老鼠后11米追老鼠,猫最少跑几米才能追上老鼠.算式
烧负掘1年前1
DeadHide 共回答了20个问题 | 采纳率100%
1.015071
2.由题可知,猫跑1步路程老鼠要跑5步,所以猫与鼠的速度比是15:4,11/(15-4)=1,1*15=15米.
英语翻译最近我刚转入某市的一所高级中学读书,在这个新环境里我遇到了许多问题.希望能得到你的一些建议.
深圳女蛙1年前4
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Recently , I have just turned to a high school in a city. I met lots of problems in this new situation and I hope that I can get some advice from you.
that I can get some advice from you也可以这么表达: that you can kindly give me some advice
英语翻译标题:推荐信尊敬的 你们好!XXX同学在广州市东圃中学(省一级高级中学)就读期间,尊敬老师,关心同学;学习刻苦,
英语翻译
标题:推荐信
尊敬的 你们好!
XXX同学在广州市东圃中学(省一级高级中学)就读期间,尊敬老师,关心同学;学习刻苦,善于思考,有专研精神;成绩优良,有进取心;性格稳重,有独立见解,是个有主见的学生,积极参加集体活动,有团结意识,合作精神.有很大的学习潜力,有一股韧劲,相信他会在贵校学有所成.特此推荐,望能批准.
推荐人XXX 东圃中学中级政治老师 班主任
时间xxx
希望能帮我手动翻译 不要借助那些工具 万分感激
sims101年前1
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你好,以下是比较专业的推荐信写法:
Recommendation Letter
To whom it may concern,
XXX is a student in Guangzhou Dong Pu High School, which is one of the provincial first-class high schools. During his study period here, he respects his teachers and is deeply concerned with his classmates; he studies very hard and is good at thinking, and moreover, he is assiduous in study; he always gets good grades and has plenty of push; he is steady and can stand on his own feet; he is also a self-determinated student and active in group activities, who has the unity consciousness and team spirit. He has unlimited potential and tenacity, which will definitely lead him to success in your school too. I recommend him as a good candidate and hope you can approve my recommendation.
Recommender: XXX
Title: Middle-level Political Teacher and Class Adviser in Dong Pu High School
mm/dd/yyyy
(2010•嘉定区二模)从某高级中学高一年级的10名优秀学生(其中女生6人,男生4人)中,任选3名学生作为上海世博志愿者
(2010•嘉定区二模)从某高级中学高一年级的10名优秀学生(其中女生6人,男生4人)中,任选3名学生作为上海世博志愿者,问恰好选到2女1男的概率是
[1/2]
[1/2]
.(用数值作答)
yuantiou1年前1
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解题思路:由题意知,本题是一个古典概型,试验发生包含的事件是从10名学生中选3名,而满足条件的事件是恰好选到2女1男,利用组合数表示出事件的个数,代入概率公式得到结果.

由题意知,本题是一个古典概型,
试验发生包含的事件是从10名学生中选3名,共有C103=120种结果,
而满足条件的事件是恰好选到2女1男,共有C62C41=60种结果,
根据古典概型概率公式得到P=[60/120]=[1/2]
故答案为:[1/2]

点评:
本题考点: 古典概型及其概率计算公式;计数原理的应用.

考点点评: 本题主要考查古典概型,解决古典概型问题时最有效的工具是列举,大纲中要求能通过列举解决古典概型问题,也有一些题目需要借助于排列组合来计数.

求"教师资格证" “高级中学教师资格证”的标准英文翻译。
求"教师资格证" “高级中学教师资格证”的标准英文翻译。
只要一个标准的翻译啊。
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教师资格证
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上海 高级中学地理课本(绿色封面,其中有中国地理和世界地理)及其配套练习册(红色封面
上海 高级中学地理课本(绿色封面,其中有中国地理和世界地理)及其配套练习册(红色封面
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谁知道哪里有卖的啊 加一用的 知道的说下啊 哪个出版社最好也说下
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配套练习册的封面也是绿色的啊.我昨天才买过~~
中国地图出版社
28块(含地图册) 在广东路河南中路路口往西 广东路310号