莫尔条纹的特点作用有哪些

Mole had said “what is most difficult in the life is the choice”.Regardless of stemming from initiative or passive,each person constantly all unceasingly is making the choice in the endless life,the life choice significance lies in with the destiny resistance,causes the life to be colorful.the life's significance does not lie in her length,but lies in her insincerity.The life may have the multiple options,some people choose lightly,also some people choose imposing; Some people choose the offer,also some people choose the gain; Some people choose the universal love,also some people choose the hatred; Some people choose persevere,also some people chose give up .Darwin once saying that “could survive the species which got down,was not these is most formidable,was also not these is most intelligent,but was these to changes makes the rapid reaction”.The infinite universe fast changing,the environment is differ in thousands of ways,the people must make the choice which adapts with it,can impel the civilized the inheritance and society's progress.We cannot not make the choice because of the worry result,also cannot be afraid loses,but does not choose has.British poet Shelley said “,if you treasure your feather,does not cause it a damage,then you will lose two wings,forever no longer can fly high the soaring”.Ms.Zhang Haidi contracts myelopathy and top digit paraplegia from 5 years old starts the destiny erroneous life,she is unable to go to school,then studies independently in the home the middle school curriculum.when 15 years old goes to the country along with the parents,for the children works as teaching gentleman,but also studies independently acupuncture medical skill free to treat an illness for the fellow villagers.Afterward she has studied independently many foreign languages,front the destiny challenge,she wages the struggle by the tenacious will and the perseverance and illness,founded own literary production enterprise,until now she creates the work which and translates to surpass 1,000,000 characters,has made the outstanding contribution to the society,sang the life song of praise which strove constantly for self-improvement.how regardless of we do choose and pay for it,we will undertake the result for this reason,this is also the positive attitude towards life.Because if indecisive does not make the choice,that is the worst choice.the history perpetual flow,the life is in a hurry the traveler; All over the sky the stars,perhaps we are only not worthy of mentioning.Because chose the smile,to face directly and to take on,the life will only then become splendid.

θ=3.14×0.057°/180°=0.001
B≈W/θ=0.01/0.001=10mm

错的

你的题是：某乙二酸溶液中H2C2O4所含的氢原子的物质的量与溶液中水分子所含的氢原子的物质的量相同,则该乙二酸H2C2O4溶液中溶质的质量百分比浓度为多少?
选B
设乙二酸溶液中含H2C2O4的物质的量为a,
溶液中H2C2O4的质量m(H2C2O4)=nM=amol*90g/mol=90ag
则溶液中H2C2O4所含的氢原子物质的量n(H)=2n(H2C2O4)=2amol
溶液中水分子所含氢原子的物质的量n(H)=2amol
溶液中水分子的物质的量n(H2O)=1/2n(H)=1/2*2amol=amol
溶液中水分子的质量m(H2O)=nM=amol*18g/mol=18ag
该乙二酸H2C2O4溶液中溶质的质量百分比浓度=90ag/(90ag+18ag)*100%=83.3%

50ml 18mol/L 的硫酸就是0.9mol,根据方程式可得2H2SO4--SO2
2------- 1
0.9------- X
所以X=0.45,但实际在发生反应时,因为硫酸浓度降低,不是浓硫酸后,不能与铜反应,所以有小于0.45mol硫酸被还原

c

我们课本就是这样写的。。。我亲自打出来的，不是复制奥
原理：指示光栅与标尺光栅叠放在一起，中间留有适当的微小间隙，并使两块光栅的刻线之间保持一很小的夹角口，两块光栅的刻线相交，当在诸多相交刻线的垂直方向有光源照射时，光线就从两块光栅刻线重和处的缝隙通过，于是就形成了明暗条纹，这些条文成为莫尔条纹。
特性：1.调整夹角即可得到很大的莫尔条纹宽度，起到了放大作用，又提高了测量精度

用法：
morsecode=morse('matlabsky baidu wacs5',0) %编码
srccode=morse(morsecode,1) %解码
morsecode(2)='.'; %修改码
srccode=morse(morsecode,1) %错误的morse码进行解码
function Dst=morse(Src,Flag)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%Author :wacs5
%%Date :20101031
%%Function :morse(莫斯密码)编码和解码
%%Argument :Src为待编码/解码的字符串
%% :Flag=0为编码,Flag=1为解码
%%Return :Dst为完成的编码/解码的字符串
%%Called Mtb :disp,find,isempty,isequal,length,nargin,strrep,warning
%%Example:
%% :morsecode=morse('matlabsky baidu wacs5',0)
%% :srccode=morse(morsecode,1)
%% :morsecode(2)='.'; srccode=morse(morsecode,1) %错误的morse码
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if nargin==1
Flag=0; %缺省为编码
end
Dst=[];
SrcAlpha=['A':'Z','1':'9','0']; %原始字母
EncAlpha={'.-','-...','-.-.','-..','.','..-.','――.','.','..','.―――','-.-','.-..','――','-.','―――','.――.','――.-','.-.','...','-','..-','...-','.――','-..-','-.――','――..','.――――','..―――','...――','.-','.','-.','――...','―――..','――――.','―――――'}; %相应的morse码
if Flag==0
disp('Encoding'); %编码
for i=1:length(Src)
if Src(i)>='a' && Src(i)