-5X3+2X4+3X2+X-1=0,求X (负5X的3次方加上2X的4次方加上3X的平方加上再减1

-5x³+2x^4+3x²+x-1=0
2x^4-2x³-3x³3x²+x-1=0
2x³(x-1)-3x²(x-1)+(x-1) = 0
(x-1)(2x³-3x²+1) = 0
(x-1)(2x³-2x²-x²+1) = 0
(x-1){2x²(x-1)-(x+1)(x-1)} = 0
(x-1)(x-1)(2x²-x-1) = 0
(x-1)(x-1)(2x+1)(x-1) = 0
x1=-1/2,x2=x3=x4=1

带求根公式

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