一式四联 英语怎么说例如 增值税发票就是一式四联的 那一式四联用英语该怎么说呢

y/3-x/6-1=3
2(x-y/2)=3(x+y/18)
两式化简得
2y-x=24
7y+6x=0
两式联立得
x=-168/19
y=144/19

ax^2+bx+c=0
ax^2+bx=-c
ax^2+bx+(b/2a)^2=(b/2a)^2-c
a(x+b/2a)=b^2-4ac/4a

前面的是纸张不带复写功能所以要用双面复写纸,后面的复写功能是纸张自带的

8/9>6/7>4/5>2/3
8/9>6/7>4/5>1/2
8/9>6/7>3/4>1/2
8/9>5/6>3/4>1/2
...

啊啊,意思应该是两样都要,身份证和户口每样（即每个不同的页面）都要六份.因为他已经说明是“一式六份”,而且“身份证复印件、户口簿复印件”之间是顿号,表明了这两样东西的每个不同页面都复印要六份.因为学籍档案,教育主管部门、学校学生档案等等都要要,所以份数多.

右边的氧原子一共是3/2(来自H2O)+1（NO）=5/2个
左边的反应物是O2分子,所以要除以2,是5/4个

1
a1*q=6① a1*q^4=48 ②
②÷① q^3=8,
∴ q=2 a1=3
2
a1*q^4=-4 ① a1*q^6=-6 ②
②÷①:q²=3/2,q=±√6/2
∴q=√6/2 ,a1=-16/9
或q=-√6/2,a1=-16/9

解三元一次方程方法就是把三个未知数变为2个
使未知数的个数越少.
②－①
得：3a＋b＝3
③－②
得：21a＋3b＝57
这样就是2元一次方程组”
就好解了.
有些要用加法、有些用减法,目的就是减少未知数.

人家老师会留一份,要给人家评委一份啊,还得有一份存档吧.n年后,你还能找到当时你写的作文,

一式三份是“triplicate”
表格一式三份是“triplicate tabulation”因为triplicate是adj.,tabulation是n..
注如果用动词词组为in triplicate
例如：
把这份文件打成一式两份
type the document in duplicate才是正确的翻译
一式四份
quadruplication
一式五份
quintuplicate

将一式中的n换为n-1,欢迎追问，望采纳

没区别,写法不同而已.使用的时候一般用一式.

the agreement is duplicated by both sides,it will be taken effected after both sides' signature

这个三段论大项在结论中周延,小项在前提中不周延,根据“在前提中不周延的项在结论中也不得周延”的规则,则小项在结论中也不得周延,那么结论应该是SOP；大前提是肯定的,大项在结论中周延,根据“在前提中不周延的项在结论中也不得周延”的规则,则大项在大前提中也应该周延,因此大前提应该是PAM；结论是否定的,前提中也应该有一个是否定的,已知大前提是肯定的,中项M在大前提中是不周延的,根据“中项在前提中至少周延一次”的规则,小前提为否定的,中项可以周延一次,所以小前提应为SOM.
其形式如下：
大前提：PAM
小前提：SOM
结 论：SOP
这是三段论第二格的AOO式.

就是从1数到49,重要的是配合呼吸吐纳.

quadruplication 是一式四份的意思
但是,5 6 7 8 9 10
没有专业的,我想就说 copy 5 6 7 8 9 10 of this

本合约未尽事宜双方协商解决:This both sides of unaccomplished matter of contract resolve through consultation.
本合约一式四份双方各执二份具有同等法律效用:this four contracts are the same,it has equal legal utility that each side holds two
本合约双方签字盖章即为有效:This contract parties come into force after signing and stamping

一式两份 in duplicate
一式三份in triplicate
一式四份in quadruplicate
一式五份in quintuplicate
后面的就直说好了,with...copy

x=0 y=-1
或x=2 y=0
解法是二式移项 x-2y=2
两边平方 x^2+4y^2-4xy=4,即x^2+4y^2-4=4xy=0
所以 x=0或y=0
x=0时,y=-1
y=0时,x=2

X=9,Y=4又三分之一
一式 加 二式得到4（x+1)=40,得到x+1=10,得到x=9
二式 减 一式得到6（y-1)=20,得到y-1=10/3,得到y=13/3.即是4又三分之一

两式相加后的不等式该取>号.
否则将会增大取值范围,使结果出现错误.
如x>=8
x>10
只能2x>18,而不能取2x>=18

x+y=1-m (1)
x-3y=5+3m (2)
(1)-(2)得：
4y=-4-4m=-4(m+1)
y=-(m+1),代入(1)得：
x=1-m -y=1-m +m+1=2
若m=x,则m=2,此时y=-(m+1)=-(2+1)=-3
若m=y,则m=-(m+1) 2m+1=0 m=-1/2
综上,得m=2或m=-1/2.

在写合同时,重大事件有人证明最好,但不般不会去公证处公证,所以一般有一个公证人,就是介乎你俩之间的这样一个人,以后如发生争议的话相关人员就可凭手中的东西作证,所以一般是一式三分,分给甲乙公证人各一份,一式五份的话可能有几位合伙人或公证人.

带进去不是L=mr²*角速度=mvr吗,有什么问题?

1 contract like has the not completely matters concerned,writtensupplements it after the discussion.2 gather identical two,both sides respectively holds

化简100A+10B=100,10A+B=10①,10000A+100B=100,100A+B=1②
①-②得-90A=9,A=-0.1
不A=-0.1代入①,B=11
所以A=-0.1,B=11

As your request,we send our order no.128 in triplicate.But this order not means we accept it without any conditions,because the price and quantity is subject to our final confirmation.
Please cable or fax us as soon as possible if you get the license,in order to confirm the offer.If there are some changes in the price or time of delivery,we will contact you.
We look forward to your early reply.

你好,一个小时六十分钟

你可以化成分钟再去相减

如果你说的是三点一十结束的话,那就是四十分钟

21*24＝12*42,63*12=36*21,12*84=21*48,
规律方程式：x*y=(1/a)x*(a)y (a＞1）

将2式乘以2可得,4f(x)+2f(1/x)=4/x+2这是3式,用3式减去一式可得3f(x)=4/x-2x+1,所以f(x)=4/3x-2x/3+1/3

In response to your request in the letter dated 12 Oct,we are glad to send you informal invoices,in quadruplicate,as enclosed.
.

卫星在空中是万有引力提供向心力,不是重力提供向心力.所以①式是错误的.又GMm/r=mv/r得v=根号下GM/r ∴v正比于根号下1/r ∴轨道半径越大,速度越小 而卫星要远离地球,做的是离心运动,要加速

选A,第一个方程组的解是指满足这两个方程的解,因此必定满足第二个方程,而第二个方程式满足
7x+3y=12的解,不一定适合
4x-5y=8,比如x=1,y=5/3,可以举反例的,还有问题了你可以去这里问问哈,裙子,
253016094

这句话本来就有问题..
如果两种语言有冲突和歧义 应该以哪种语言为准?
The contract shall be written in Chinese and in English,shall have two originals and each party will have one,Both language versions are equally authentic.

We take pleasure in enclosing the proforma invoice No.THD 2011-0053 in triplicate as per the 40 boxes tea set which you are interested in buying at USD 16.3 / set CFR C1 Alexandria .

The contract has been written in triplicate.It is activated once signed.Please sign or seal on the signature blank,as a sign of agreement.Each of us keeps one of them.

先求二式再求一式比较方便.
用C(m,k)表示m中选k的组合数,并约定k < 0或k > m时C(m,k) = 0.
首先,有组合恒等式∑{0 ≤ i ≤ k} C(m,i)C(n,k-i) = C(m+n,k) ①.
证明只需考虑恒等式(1+x)^m·(1+x)^n = (1+x)^(m+n)两边的k次项系数.
∵k·C(2n,k) = 2n·C(2n-1,k-1),
∴∑{0 ≤ k ≤ n-1} k²·C(2n,k)²
= 4n²·∑{1 ≤ k ≤ n-1} C(2n-1,k-1)²
= 4n²·∑{0 ≤ k ≤ n-2} C(2n-1,k)².
而由①,C(4n-2,2n-1) = ∑{0 ≤ k ≤ 2n-1} C(2n-1,k)C(2n-1,2n-1-k)
= ∑{0 ≤ k ≤ 2n-1} C(2n-1,k)²
= 2·C(2n-1,n-1)²+ ∑{0 ≤ k ≤ n-2} C(2n-1,k)² + ∑{n+1 ≤ k ≤ 2n-1} C(2n-1,k)²
= 2·C(2n-1,n-1)²+ ∑{0 ≤ k ≤ n-2} C(2n-1,k)² + ∑{n+1 ≤ k ≤ 2n-1} C(2n-1,2n-1-k)²
= 2·C(2n-1,n-1)²+ ∑{0 ≤ k ≤ n-2} C(2n-1,k)² + ∑{0 ≤ k ≤ n-2} C(2n-1,k)²
= 2·C(2n-1,n-1)²+ 2·∑{0 ≤ k ≤ n-2} C(2n-1,k)²,
∴∑{0 ≤ k ≤ n-2} C(2n-1,k-1)² = C(4n-2,2n-1)/2-C(2n-1,n-1)²,
∴∑{0 ≤ k ≤ n-1} k²·C(2n,k)² = 2n²·C(4n-2,2n-1)-4n²·C(2n-1,n-1)² ②.
∵k·C(2n,k) = 2n·C(2n-1,k-1),(2n-k)·C(2n,k) = 2n·C(2n-1,k),
∴∑{0 ≤ k ≤ n-1} k(2n-k)·C(2n,k)²
= 4n²·∑{1 ≤ k ≤ n-1} C(2n-1,k-1)C(2n-1,k)
= 4n²·∑{0 ≤ k ≤ n-2} C(2n-1,k)C(2n-1,k+1).
而由①,C(4n-2,2n-2) = ∑{0 ≤ k ≤ 2n-2} C(2n-1,k)C(2n-1,2n-2-k)
= ∑{0 ≤ k ≤ 2n-2} C(2n-1,k)C(2n-1,k+1)
= C(2n-1,n-1)²+ ∑{0 ≤ k ≤ n-2} C(2n-1,k)C(2n-1,k+1) + ∑{n ≤ k ≤ 2n-2} C(2n-1,k)C(2n-1,k+1)
= C(2n-1,n-1)²+ ∑{0 ≤ k ≤ n-2} C(2n-1,k)C(2n-1,k+1) + ∑{0 ≤ k ≤ n-2} C(2n-1,k+1)C(2n-1,k)
= C(2n-1,n-1)²+ 2·∑{0 ≤ k ≤ n-2} C(2n-1,k)C(2n-1,k+1),
∴∑{0 ≤ k ≤ n-2} C(2n-1,k)C(2n-1,k+1) = C(4n-2,2n-2)/2-C(2n-1,n-1)²/2,
∴∑{0 ≤ k ≤ n-1} k(2n-k)·C(2n,k)² = 2n²·C(4n-2,2n-2)-2n²·C(2n-1,n-1)² ③.
②+③得2n·∑{0 ≤ k ≤ n-1} k·C(2n,k)²
= 2n²·(C(4n-2,2n-1)+C(4n-2,2n-2))-6n²·C(2n-1,n-1)²
= 2n²·C(4n-1,2n-1)-6n²·C(2n-1,n-1)²,
∴∑{0 ≤ k ≤ n-1} k·C(2n,k)² = n·C(4n-1,2n-1)-3n·C(2n-1,n-1)².

3+6=9
8-7=1
4x5=20

Note: This form contains three copies to be kept by the employee, the direct supervisor of employee, and Human Resources.

写几份只是分发给合同相关单位或人员保存归档,没什么实际意义.

甲看错a,则他的二式没错
所以那他的解代入二式
12+b=2
b=10
乙看错b
则一式正确,代入
5a+20=15
a=-1
所以原式=(-1)^2006+(-1)^2005=1-1=0

This contract shall be provided in two copies,with each party holding one copy.

log以（根号2-1）为底的（3-2根号2）
=log以（根号2-1）为底的（根号2-1）^2
=2

可以先消掉x
一式乘以(-5)为：-20x+40y=-75
二式乘以4为：-20x+40y=-120
然后相减
晕,你的题出错了.

Am pleased to be able to under the heading of goods to deal with you.We will mail another letter No.1002,the sales contract in duplicate,please sign and return an archive for our side.
It is emphasised that the banks must first class out to the beneficiaries of letters of credit for our side.Received a letter of credit,we will be arrangements for the timely shipment.We believe that the goods will be satisfied with your side

According to your request,it is sent to you the shirt Diyierba the form of an invoice for two-thirds.
However,the invoice does not mean that you accept unconditionally the orders,because our price and volume subject to further confirmation.
Once you have had the necessary permits,telex or fax to notify the Chinese side,in order to confirm our offer.
At the same time,if the price or delivery time of any change,then we will contact with you.
You hope to get further information.

This contract was signed on March 29,1998.It was in duplicate,each of which was written in English and Chinese,and both copies are equally authentic.

右边的氧原子一共是3/2(来自H2O)+1（NO）=5/2个
左边的反应物是O2分子,所以要除以2,是5/4个