(1)x²-y²/xy×x/x-y (2)a/a²+6a+9÷a平方/a+3

kaixindaxiao2022-10-04 11:39:541条回答

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(x²-y²)/(xy)×(x/x-y)
=(x+y)(x-y)/(xy)×(x/x-y)
=(x+y)/y
(a/a²+6a+9)÷(a平方/a+3)
=a/(a+3)²×(a+3)/a²
=1/[a(a+3)]
1年前

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