a^4b^4-8a^2b^2+16

8a^2b^2-a^4-16b^4
=-(a^4-8a^2b^2+16b^4)
=-(a^2-4b^2)^2
=-(a+2b)^2(a-2b)^2

1）原式=2(a^4+b^4-2a²b²)=2(a²-b²)²=2(a+b)²(a-b)²
2）原式=-(16ab+8ab+b²)=-(4a+b)²
3）原式=(x²-5x)²-2(x²-5x)+1=(x²-5x-1)²
4）原式=(m-1)²[4m²-12m+9]=(m-1)²(2m-3)²

原式=a²-b²+b²-2ab=a²-2ab
当a=2,b=-1时,原式=4+4=8

(-1/2ab^3)^3*(-1/4ab)*(-8a^2b^2)^2
=(-1/8a^3b^9)*(-1/4ab)*(64a^4b^4)
=(-1/8)*(-1/4)*64*a^(3+1+4)*b^(9+1+4)
=2a^8b^14

2(a^2+b^2)^2-8a^2b^2
=2a^4+4a^2b^2+2b^4-8a^2b^2
=2a^4-4a^2b^2+2b^4
=2(a^2-b^2)^2
=2(a+b)^2(a-b)^2

约分:(1+2a^2b^2)^2-8a^2b^2/(1-a^2b^2)(1+a^6b^2)
悬赏分：0 - 离问题结束还有 14 天 4 小时
约分:(1+2a^2b^2)^2-8a^2b^2/(1-a^2b^2)(1+a^6b^2)
回答：
(1+2a^2b^2)^2-8a^2b^2/(1-a^2b^2)(1+a^6b^2)=
（1-2a^2b^2)^2/(1-a^2b^2)(1+a^6b^2)=?
明白不?
下面是不可能约分的,没有公因式,所以啊,阁下题目一定有错啦
重新检查下看看

15n^3分之4a^4b^2)/(35n^2分之-8a^2b^2)
=15n^3分之4a^4b^2)* (-8a^2b^2 分之35n^2)
=a^2/3n)*(7/-2)
=-7a^2/6n

a^4-8a^2b^2+16b^4
=(a^2-4b^2)^2
=[(a+2b)(a-2b)]^2
=(a+2b)^2(a-2b)^2
括号中应填(a-2b)^2

解
(a+2b)(a-2b)(a^4-8a²b²+16^4)
=(a²-4b²)(a²-4b²)²
=(a²-4b²)³
=a^6+3×a²×(4b²)²-3×(a²)²×(4b²)-64b^6
=a^6+12a²b^4-12a^4b²-64a^6
(a-b)³=a³+3ab²-3a²b-b³

a^4-8a^2b^2+16b^4=(a^2)^2-8a^2b^2+(4b^2)^2={a^2-(4b^2)^2}^2={(a+2b)(a-2b)}^2
-4a^3+16a^2b-16ab^2=-4a(a^2+4ab-4b^2)=-4a(a-2b)^2
4(2x-1)^2-9x^2={2(2x-1)}^2-{3x}^2={4x-2}^2-{3x}^2=(4x-2-3x)(4x-2+3x)==(x-2)(7x-2)
4(x^2+1)^2-16x^2=4{(x^2+1)^2-4x^2}=4{(x^2+1)+2x}{(x^2+1)-2x}=4(x+1)^2(x-1)^2
(a^2+4)^2-16a^2= (a^2+4)^2-(4a)^2= {(a^2+4)-4a}{(a^2+4)+4a}=(a-2))^2}(a+2))^2

(4ab³-8a²b²)÷4ab+(2a+b)(2a-b)
=[4ab(b²-2ab)]÷4ab+(4a²-b²)
=b²-2ab+4a²-b²
=4a²-2ab
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a^4-8a^2b^2+16b^4
=(a²-4b²)²
=(a+2b)²(a-2b)²

原式=-(a²-4b²)²
=-(a+2b)²(a-2b)²

1) 1/9a^2+1/3ab+1/4b^2
=1/36×(4a^2+12ab+9b^2
=1/36(2a+3b)^2
2)1/8a^3b-1/8a^2b^2+1/32ab^3
=1/32ab×(4a^2-4ab+b^2)
=1/32ab(2a-b)^2