SQLServer如何查看表结构呢？有同oracle的desc一样命令吗？

use Roy --数据库
go
--2005实现数据库表字段属性统计(2000里的系统表sysproperties描述表不存在，2005里用sys.extended_properties视图替代)
select
[表名]=c.Name,
[表说明]=isnull(f.[value],""),
[列名]=a.Name,
[列序号]=a.Column_id,
[标识]=case when is_identity=1 then "√" else "" end,
[主键]=case when exists(select 1 from sys.objects x join sys.indexes y on x.Type=N"PK" and x.Name=y.Name
join sysindexkeys z on z.ID=a.Object_id and z.indid=y.index_id and z.Colid=a.Column_id)
then "√" else "" end,
[类型]=b.Name,
[字节数]=case when a.[max_length]=-1 and b.Name!="xml" then "max/2G"
when b.Name="xml" then "2^31-1字节/2G"
else rtrim(a.[max_length]) end,
[长度]=case when ColumnProperty(a.object_id,a.Name,"Precision")=-1 then "2^31-1"
else rtrim(ColumnProperty(a.object_id,a.Name,"Precision")) end,
[小数]=isnull(ColumnProperty(a.object_id,a.Name,"Scale"),0),
[是否为空]=case when a.is_nullable=1 then "√" else "" end,
[列说明]=isnull(e.[value],""),
[默认值]=isnull(d.text,"")
from
sys.columns a
left join
sys.types b on a.user_type_id=b.user_type_id
inner join
sys.objects c on a.object_id=c.object_id and c.Type="U"
left join
syscomments d on a.default_object_id=d.ID
left join
sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.Column_id and e.class=1
left join
sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1