蜗轮与蜗杆传动比的计算

Worm Face Modulus
Worm first few
L helix angle
Spiral direction
Worm axial section profile angle
Worm Drawing No. matching
Worm pitch cumulative tolerance
2A-type worm gea

　　Abstract
　　Traditional mechanical speedometer output power from the wheels,worm gear drive shaft driven by the flexible shaft tip synchronous rotation,so that the other side of the fixed and flexible shaft of the permanent magnet synchronous rotation followed,resulting in rotating magnetic field of the magnetic field in the rotating disk,it disk rotation speed so that,together with the table pointer to the occurrence of the deflection.When the electromagnetic torque and resistance torque generated by the spring balance,the indicators remain at a deflection point of view.Pointer deflection is proportional to angle and speed,so that its speed can be used.
　　Mechanical defects in the speed table is obvious.As the dial indicator shaft deflection is proportional to the degree of rotation of the magnetic force generated,when a lower speed,the magnetic force smaller,with larger fluctuations in speed changes.Therefore,the low-speed table pointer when the swing's intense,measurement and display accuracy is not high.The rear engine vehicle,the speedometer pointer to the deflection by the transmission power transmitted by flexible shaft,such as driver's cab,a long flexible shaft arrangement is bound to,how long will such a rotating shaft from the structural arrangement of properly,is certainly a very difficult task.In addition,the traditional mechanical speedometer all the defects,the instrument has gradually been eliminated
　　This article describes the design of the speed and odometer to the smallest single-chip microcomputer system and the Hall sensor at the core.Different speed sensor into the different frequency pulse signal input to the control and calculation of single-chip,and then show that the use of LED modules,making the speed of electric bicycle mileage data and visual display to the user.
　　The system by the Hall sensor,RC filter circuit,microcontroller AT89S8252,systematic LED display module,data storage circuit.Hall sensor which includes signal amplification and waveform shaping.Treatment of test signals to enlarge the purpose of treatment is to reduce the magnitude of the signal measurement requirements; wave transformation and wave shaping circuit is used to convert the amplified signal can be connected with the single-chip TTL signal; through the MCU can set up internal Timer T1 input pin T0 pulse control,this can be calculated accurately pin T0 added to the unit time detected pulses; design speed display using LED modules,obtained through the conversion rate of mileage using I2C bus and through E2PROM to store not only save the required mouth-line single-chip microcomputer and peripheral devices,as well as simplifying the display part of the software programming
　　In this paper,among the first to design the necessary equipment odometer detail of the design problems are described; the latter part of the hardware and software design and the realization of made a serious analysis; and then gives the system modeling process and the corresponding system model,on the basis of a control simulation,and simulation results are compared.
　　The odometer of the design is simple in structure,low costs,and show the clear advantages of stable and reliable.And can be expanded to include the function of table speed,and more convenient to understand the situation you are now.
　　Key words:single-chip,LED digital tube,Hall sensor,EEPROM memory.

如果是1：1练习手绘的话,其实没有什么具体的步骤可言,根据个人习惯而定.
不过通常边框开始画起,然后可以实际量取蜗杆主体的位置参数,在A2图纸上定下蜗杆的基点,从蜗杆开始画,然后是箱体,最后标注尺寸,和技术要求.
注意铅笔的使用,因为实体轮廓线要求什么黑又亮来着,虚线尺寸线要求也有细读要求,可以考虑0.5自动铅笔草图底稿,然后用削好的铅笔重新画到作图要求.可在手上垫上一张面巾纸作图,能保证作图干净,而且要经常擦拭三角板和直尺以保证没有铅笔屑,反正手绘一是保证角度,垂直度比较费劲,再就是作图的整洁程度不好做.多注意即可.

1.传动比i=n1/n2=z2/z1;
∴n2=n1*z1/z2=1380*3/69 r/min=60r/min;
2.z2=z1*i=z1*n1/n2=3*1380/45=92;

你好,你的问题提得比较专业,我担心自己的水平不够,误了你的事,我试着回答,请你权且当作参考.
1、用键做周向定位是没有问题的,问题是你的蜗轮蜗杆的运动速度及受力情况如何.一般地说重载、或高速情形拟选用花键、双平键或半圆键.记住：同样宽度的半圆键比平键的载荷能力强得多.轻载、慢速就无所谓了.
一般来说,蜗轮的轴向可以用弹性挡圈定位,因为蜗轮的轴向力不会很大,不过加工有加工误差,装配有装配误差,所以你设计时要考虑怎样保证在这些误差存在的情形下能保证装配到位,否则即便你图纸上画得再正作,人家装进去对不上又没有办法调整,那人家会说：工程师怎么在设计的?你吃亏就大了.
蜗杆的轴向能否用弹性挡圈那要看情况而定,因为蜗杆承受的轴向力是比较大的,最常见的定位方式是：轴肩定位轴承,两端闷盖定位轴承,这样有个好处,可以调整轴的定位间隙.
下面回答你的第二个问题：
蜗轮蜗杆传动是一种比较容易实现自锁的传动,但绝对不是都能自锁,蜗杆的自锁条件：γ≤β
式中：γ——蜗杆的螺旋升角 β——当量摩擦角

所以如果你设计蜗杆是主动件那必须保证γ≤β
所以如果你设计蜗轮是主动件那必须保证γ≥β
设计蜗杆传动,还有要注意如下问题：
1、材料和热处理；2、润滑及工况；3、传动比
前两点我就不展开说了,因为题目太大,第3点我说一下,蜗杆传动的传动比可以做得很大,理论上可以做传动比为1000的蜗杆传动,但实际中不要冒这个险,这是因为传动比大,蜗杆的跨度必然大,蜗杆跨度大对蜗杆的钢性要求就高,那对材料、热处理要求也会高,加工难度大会使问题变得很复杂.一般控制在80以下比较稳妥.
好了,这些天我很忙,以后再聊,祝你顺利成功!

蜗杆传动相当于斜齿轮与直齿条传动——就传动原理而言,是这样的.为什么蜗轮的直径是d=mz 而斜齿轮的直径d=mz /cos β——这是因为,蜗轮的模数m,是端面模数,是标准值；而斜齿轮的模数,是法面模数,是标准值.斜齿轮端面...

蜗轮、蜗杆的计算公式：
1,传动比=蜗轮齿数÷蜗杆头数
2,中心距=（蜗轮节径+蜗杆节径）÷2
3,蜗轮吼径=（齿数+2）×模数
4,蜗轮节径=模数×齿数
5,蜗杆节径=蜗杆外径-2×模数
6,蜗杆导程=π×模数×头数
7,螺旋角（导程角）tgB=（模数×头数）÷蜗杆节径

蜗杆传动比：90÷1=60
卷筒转速：960÷60=16r.p.m

tanα=Z1/q;（α为导程角）
其中q=d1/m,这里的模数m是蜗杆的模数,d1是蜗杆的分度圆直径,q是直径系数,而d1和m是有国家标准规定的,可以查国标.你的m=4,对应d1=40或71.代入上式就可以求得α了.

1:60
960/60(如果求线再乘周长）

蜗轮是由齿轮“变化”过来的,但是有细节的变化；对照蜗轮喉圆直径、顶圆直径计算公式,再对照标准齿轮齿顶圆计算公式,会发现“相当于标准齿轮的蜗轮”的“齿顶高系数”会很大的；而最少齿数与齿顶高系数有关,所以蜗轮不发生根切的最小齿数是27齿.（通过逆向计算,蜗轮的“齿顶高系数相当于1.5792）
供参考.

看你精度要求了,简单的可以用接近开关,在转轴上加个铁凸

增速传动的传动比是小于1的.大于1的肯定不是增速传动,而且蜗杆传动极少有倒过来用的,绝大多数都是蜗杆主动.不知道你是在什么地方看到这个东东.

道理都是差不多的
在螺旋传动中的左右手法则
螺母或螺杆的移动方向与螺纹的旋向及构件的转动方向有关.
根据螺纹的旋向选择哪只手.
左旋螺纹用左手；右旋螺纹用右手.
四指表示转动的方向.
大拇指就表示转动构件的移动方向.
此方法也可以反过来用,通过了解螺母与螺杆的相对运动关系从而推出螺纹的旋向.
如果是斜齿轮的话,要通过主动轮判断左右旋,从而确定是左手还是右手
四指表示主动轮的转向,大拇指表示主动轮的轴向力方向.
大拇指反向为从动轮的轴向力方向.
如果是涡轮蜗杆的话
蜗杆是主动件,按照蜗杆判断左旋还是右旋
四指表示蜗杆的转动方向
拇指表示蜗杆的轴向力方向
拇指的反方向表示涡轮的圆周力方向
蜗杆的圆周力与涡轮的轴向力之间是大小相等方向相反的关系
涡轮的圆周力与蜗杆的轴向力之间是大小相等方向相反的关系
关于涡轮蜗杆的受力具体分析
蜗杆受力
径向力不必说了
蜗杆所受圆周力的方向与它的转向相反
蜗杆所受轴向力方向根据左右手法则确定
涡轮受力
径向力不说了
蜗轮的圆周力与蜗杆的轴向力之间是大小相等方向相反的关系
蜗轮的轴向力与蜗杆的圆周力之间是大小相等方向相反的关系