- coco
-
原式=x³-x-x+1
=x(x²-1)-(x-1)
=x(x-1)(x+1)-(x-1)
=(x-1)(x²+x-1)
有理数范围内就分解到这里,
实数范围内还可以再分。
- S笔记
-
原式
=x(x²-1)-(x-1)
=(x-1){x(x+1)-1}
=(x-1)(x²+x-1)
- wio
-
可以:
=ⅹ³-x²+x²-2x+1
=x²(x-1)+(x-1)²
=(ⅹ-1)(ⅹ²+ⅹ-1)
- 豆豆staR
-
可以,用大除法
化为
(x-1)(x²+x-1)
- 可可
-
=X(X^2一1)一X+1
=X(X十l)(X一1)一(X一丨)
=(x一1)(X^2十X一1)
- max笔记
-
图
- 马老四
-
x³-2x+1
=x³-x-x+1
=(x³-x)-(x-1)
=x(x²-1)-(x-1)
=x(x+1)(x-1)-(x-1)
=(x-1)[x(x+1)-1]
=(x-1)(x²+x-1)
- 真可
-
(x-1)(x2+x+1)
- wpBeta
-